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Consmight
Regular Visitor

Matrix - Identifying Repeating Values

Hello,

 

I'm trying to add an additional column to this matrix that returns to a value if a percent is repeated three times in a row. For example if a URL row has three 0%'s across in order, I want a column at the end to provide a value. How would I do this?

 

example.JPG

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @Consmight ,

 

Based on your description, I'd suggest you change the sub-column total.

Flag = 
var _pre1=CALCULATE(SUM('Table'[Percent %]),FILTER(ALLSELECTED('Table'),[URL]=MAX('Table'[URL]) && [Index]=MAX('Table'[Index])-1))
var _pre2=CALCULATE(SUM('Table'[Percent %]),FILTER(ALLSELECTED('Table'),[URL]=MAX('Table'[URL]) && [Index]=MAX('Table'[Index])-2))
return IF(  SUM('Table'[Percent %])=_pre1&& SUM('Table'[Percent %]) =_pre2 && _pre1<>BLANK() , 1)
Sub-total = 
var _val=IF(MAXX('Table',[Flag])<>BLANK(),"Has >=3 consecutive values")
return
IF(HASONEVALUE('Table'[Index]),SUM('Table'[Percent %]),_val)

Eyelyn9_0-1637806848027.png

 

 

Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
Anonymous
Not applicable

Hi @Consmight ,

 

Based on your description, I'd suggest you change the sub-column total.

Flag = 
var _pre1=CALCULATE(SUM('Table'[Percent %]),FILTER(ALLSELECTED('Table'),[URL]=MAX('Table'[URL]) && [Index]=MAX('Table'[Index])-1))
var _pre2=CALCULATE(SUM('Table'[Percent %]),FILTER(ALLSELECTED('Table'),[URL]=MAX('Table'[URL]) && [Index]=MAX('Table'[Index])-2))
return IF(  SUM('Table'[Percent %])=_pre1&& SUM('Table'[Percent %]) =_pre2 && _pre1<>BLANK() , 1)
Sub-total = 
var _val=IF(MAXX('Table',[Flag])<>BLANK(),"Has >=3 consecutive values")
return
IF(HASONEVALUE('Table'[Index]),SUM('Table'[Percent %]),_val)

Eyelyn9_0-1637806848027.png

 

 

Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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