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Hi all,
I have a table TICKETS that has date columns [ created ] , [ assigned ] , [ resolved ]
I want to display a line chart of all the tickets with those three separate lines as they all have separate dates and see the count of tickets relative to the values in those columns.
I created a measure of all the tickets (COUNTROWS[ Tickets ]) and tried applying that to the VALUES and the columns to the AXIS and Secondary Axis - yet the numbers displayed on the line chart are off. Only the Created number is correct.
I'm having a hard time wrapping my head around this.
Solved! Go to Solution.
Hi @bixby ,
Maybe I understand what you mean,you need to create an unrelated calendar table as an x-axis or slicer.
Then create 4 measures like this:
Measure =
var count_ = CALCULATE(COUNT('Table (3)'[ticket_id]),FILTER('Table (3)','Table (3)'[created_date].[Date]=MAX('Table'[Date])))
return IF(ISBLANK(count_),0,count_)
Best Regards,
Liang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi,
could you share some sample data or an expected result you are looking for?
Regards
Desired outcome:
Apply ONE date slicer to multiple date values in a line chart (chart shows number of tickets by date - lines represent "created", "assigned", "resolved", "unassigned"):
Example line chart
Sample Data:
ticket_id | created_date | assigned_date | resolved_date | unassigned_date |
1 | 7/29/2020 8:59:34PM | 7/29/2020 9:19:34PM | 7/30/2020 12:59:34PM | |
2 | 7/29/2020 9:59:34PM | 7/29/2020 | ||
3 | 7/29/2020 10:59:34PM | 7/29/2020 9:25:34PM | 8/3/2020 6:59:34PM |
Hi @bixby ,
Maybe I understand what you mean,you need to create an unrelated calendar table as an x-axis or slicer.
Then create 4 measures like this:
Measure =
var count_ = CALCULATE(COUNT('Table (3)'[ticket_id]),FILTER('Table (3)','Table (3)'[created_date].[Date]=MAX('Table'[Date])))
return IF(ISBLANK(count_),0,count_)
Best Regards,
Liang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.