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Anonymous
Not applicable

How to Round to Start Hour, DirectQuery!

Dear all,

I need to round current time to the start hour, but i'm working in direct query.
1.PNG
When i try do this on "edit query" tell me that's not supported in direct query mode.

I need to work whith direct query, i cant export all data.

It is possible to do it in another way?

Thanks!

1 ACCEPTED SOLUTION
v-lid-msft
Community Support
Community Support

Hi @Anonymous ,

 

We can create a calculated column to meet your requirement:

 

StartHour = 
[DateTime]
    - DIVIDE ( MINUTE ( [DateTime] ), 60 * 24, 0 )
    - DIVIDE ( SECOND ( [DateTime] ), 3600 * 24, 0 )

 

11.PNG

 


Best regards,

 

Community Support Team _ Dong Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

6 REPLIES 6
v-lid-msft
Community Support
Community Support

Hi @Anonymous ,

 

We can create a calculated column to meet your requirement:

 

StartHour = 
[DateTime]
    - DIVIDE ( MINUTE ( [DateTime] ), 60 * 24, 0 )
    - DIVIDE ( SECOND ( [DateTime] ), 3600 * 24, 0 )

 

11.PNG

 


Best regards,

 

Community Support Team _ Dong Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

Solved

StartHour =
MROUND(
([Data_Hora]
- DIVIDE ( MINUTE ( [Data_Hora] ); 60 * 24; 0 )
- DIVIDE ( SECOND ( [Data_Hora] ); 3600 * 24; 0 )); TIME ( 1; 0; 0 ) ) + TIME ( 0; 0; 0 )

Hi @Anonymous ,

 

Glad to hear that you have resolved your problem.

 

Best regards,

 

Community Support Team _ Dong Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

It is because time is not only in seconds.

1.PNG

 

Is it possible to round the date to seconds?

Anonymous
Not applicable

One more thing you do that with new mesure or new column?

I only can do it with a new column, but i noticed when i try to count all values they give me wrong results

 

1.PNG

 

I have values ​​in the order of tens and should have in the thousands.

Try to use relationships with the calendar, but get the same results.

Thank you

Anonymous
Not applicable

Works it, thanks

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