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I have a few shapes that is "on top" of a matrix specifically... As the matrix has many columns, I would need to scroll left/right quite often, but the shape does not "follow" the visualization... Is there a way to fix it so that when I scroll left/right, the shape affixed ontop would follow?
Thanks.
Solved! Go to Solution.
Hi @WestWinter ,
Agree with ponnusamy .
Unfortunately, It is by design. There is no option to acheive it now. You can submit an idea for it in Power BI Idea Forums to help advance the implementation of this feature.
Hope it helps,
Community Support Team _ Caitlyn
If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
Hi @WestWinter ,
Agree with ponnusamy .
Unfortunately, It is by design. There is no option to acheive it now. You can submit an idea for it in Power BI Idea Forums to help advance the implementation of this feature.
Hope it helps,
Community Support Team _ Caitlyn
If this post helps then please consider Accept it as the solution to help the other members find it more quickly.
bump
@WestWinter : If you explain more on your intention of keeping that shape on top matrix, we probably can suggest some workaround. Share the reason for that shape on matrix .
Hi @WestWinter 
I think this post can help you to solve your issue.
Accept this post as a solution if it solved your issue
Have a good day
I don't want to freeze any elements within the matrix - but shapes ontop of it when I scroll to the left/right
@AntoineTRICHET As below... You can see it's a matrix that is scrollable left to right... I have a shape that is ontop of the revenue columns for the first categorization... However, I found out that when I scroll to the right, the shape will accompany it i.e. cover up the small/medium columns when scrolled to the right
@WestWinter : I don't think its possible since they are two different visuals and you can not control the property of one visual dynamically based on change in property on another visual (in your example - scrolling the matrix horizontally).
If this post helps, then please consider Accepting it as the solution, Give Kudos to motivate the contributors.
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