Join us at FabCon Atlanta from March 16 - 20, 2026, for the ultimate Fabric, Power BI, AI and SQL community-led event. Save $200 with code FABCOMM.
Register now!The Power BI Data Visualization World Championships is back! It's time to submit your entry. Live now!
Hi everyone,
I want to find 2 and 3 consecutive rows where Index equals 1 and show the results as below.
Can you please help me. I'd like to use DAX, not power query as I can't go back to query at this step.
Thanks so much!
| Index | 2 consecutive rows (result) | 3 consecutive rows (result) |
| 1 | 1 | 0 |
| 1 | 1 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 0 | 0 | 0 |
| 1 | 0 | 0 |
| 0 | 0 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
| 1 | 1 | 1 |
Solved! Go to Solution.
You may add an index column in Query Editor and use DAX below to add a calculated column.
Column =
VAR c = 2
RETURN
IF (
Table1[Index] = 0
||
VAR i = Table1[Index.1]
VAR p =
MAXX (
FILTER ( Table1, Table1[Index.1] < i && Table1[Index] = 0 ),
Table1[Index.1]
)
VAR n =
MINX (
FILTER ( Table1, Table1[Index.1] > i && Table1[Index] = 0 ),
Table1[Index.1]
)
RETURN
IF ( ISBLANK ( n ), MAX ( Table1[Index.1] ) + 1, n )
- IF ( ISBLANK ( p ), MIN ( Table1[Index.1] ) - 1, p )
- 1
< c,
0,
1
)
The Power BI Data Visualization World Championships is back! It's time to submit your entry.
| User | Count |
|---|---|
| 52 | |
| 41 | |
| 32 | |
| 26 | |
| 24 |
| User | Count |
|---|---|
| 131 | |
| 118 | |
| 57 | |
| 45 | |
| 43 |