Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Join us for an expert-led overview of the tools and concepts you'll need to become a Certified Power BI Data Analyst and pass exam PL-300. Register now.

Reply
mstefancik
Advocate IV
Advocate IV

Distinctcount based on two columns

Hello,

 

I have got 2 tables with different columns, but wto columns are same, date and customerID. I would like to do distinctcount to count all customerIDs from these two tables.

 

dc.PNG

As shown in the picture, correct result I am expecting is 4.

 

Any suggestions? Thx

1 ACCEPTED SOLUTION
sdjensen
Solution Sage
Solution Sage

Hi @mstefancik,

 

You could try this:

 

First calculate a new table having the values of CustomerID from Table1 and Table2

Table = UNION (VALUES( 'Table1'[CustomerID] ), VALUES (Table2[CustomerID] ) )

 

And then create a measure that counts the distinct values in the new table

Distinct Customers = DISTINCTCOUNT('Table'[CustomerID])

 

/sdjensen

View solution in original post

3 REPLIES 3
v-qiuyu-msft
Community Support
Community Support

Hi @mstefancik,

 

In addition, you can also use "Append Queries" feature in Query Editor to append Table2 to Table1. The new table looks like below:

z1.PNG

z2.PNG

 

Then create a measure to return the count of distinct values:

 

z3.PNG

 

If you have any question, please feel free to ask.

 

Best Regards,
Qiuyun Yu

Community Support Team _ Qiuyun Yu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
sdjensen
Solution Sage
Solution Sage

Hi @mstefancik,

 

You could try this:

 

First calculate a new table having the values of CustomerID from Table1 and Table2

Table = UNION (VALUES( 'Table1'[CustomerID] ), VALUES (Table2[CustomerID] ) )

 

And then create a measure that counts the distinct values in the new table

Distinct Customers = DISTINCTCOUNT('Table'[CustomerID])

 

/sdjensen

An alternative solution could be to select the distinct values into you table and then just create a count of the rows in your new table - I would suspect this approach to be faster, but you really need to test this.

 

Table:

Table = DISTINCT( UNION (VALUES( 'Table1'[CustomerID] ); VALUES (Table2[CustomerID] ) ) )

Measure:

Distinct Customers = COUNTROWS('Table')
/sdjensen

Helpful resources

Announcements
Join our Fabric User Panel

Join our Fabric User Panel

This is your chance to engage directly with the engineering team behind Fabric and Power BI. Share your experiences and shape the future.

June 2025 Power BI Update Carousel

Power BI Monthly Update - June 2025

Check out the June 2025 Power BI update to learn about new features.

June 2025 community update carousel

Fabric Community Update - June 2025

Find out what's new and trending in the Fabric community.