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Hi Community..!!
| date | name |
| 16-May | ABC |
| 16-May | XYZ |
| 16-May | WOP |
| 17-May | ABC |
| 17-May | ABC |
| 18-May | ABC |
| 17-May | XYZ |
| 17-May | XYZ |
| 17-May | XYZ |
| 17-May | ABC |
expected output is :
| name | count |
| ABC | 3 |
| XYZ | 2 |
| WOP | 1 |
please refer the above images ,
name should be counted with respect to date.
ABC coming thrice in date 17-May then also it is counted as one.
will u please help me to do that?
waiting for quick response.
Solved! Go to Solution.
HI
Distinctcount(table[name])
Hi @Anonymous
It is not matching with expected output.
U can refer the expected output what I have mentioned.
Ppatil
Excuse me; Please find the code for the measure
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