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Penn
Resolver I
Resolver I

Create a mesure to check if all rows in one column has only one value

Hi all,

 

Here's a very simple example. There are 3 students, and there is a date filter on the report.

StudentCourseExam DateResult
S001MBA6011/08/2019Fail
S001MCS6015/09/2019Pass
S001MBA6077/09/2019Pass
S001MBA6049/09/2019Pass
S001MBA60521/10/2019Pending
S002MCS6077/08/2019Fail
S002MBA6058/09/2019Pass
S002MBA60323/10/2019Pending
S003MCS6015/08/2019Pass
S003MBA6077/09/2019Pass
S003MCS6037/09/2019Pass
S003MBA6058/09/2019Pass
S003MBA6059/10/2019Pass

 

I want to create a measure to count the students passed all courses within a certain time frame.

 

Say if the date filter in from Aug 2019 to Oct 2019, the result should be 1 as only Student S003 has passed all exams in this time frame. But if I adjust the filter to look at Sep 2019 only, the result should be 3 as all 3 students have passed all exams in September.

 

The measure that I wrote only works then I put it in a table with [Student] column in it. How can I return the value in a card?

Count All Pass = CALCULATE(DISTINCTCOUNT('Table'[Student]), FILTER(ALLEXCEPT('Table', 'Table'[Student]), AND(MAX('Table'[Result]) = "Pass", MIN('Table'[Result]) = "Pass")))

 

 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @Penn ,

You can try to use following measure formula if it suitable for your requirement:

 

Passed Student Count=
COUNTROWS (
    FILTER (
        SUMMARIZE (
            ALLSELECTED ( T3 ),
            [Student],
            "A Course", DISTINCTCOUNT ( T3[Course] ),//all courses
            "P Course", CALCULATE ( DISTINCTCOUNT ( T3[Course] ), T3[Result] = "Pass" )//passed courses
        ),
        [A Course] = [P Course]
    )
)

 

Regards,

Xiaoxin Sheng

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi @Penn ,

You can try to use following measure formula if it suitable for your requirement:

 

Passed Student Count=
COUNTROWS (
    FILTER (
        SUMMARIZE (
            ALLSELECTED ( T3 ),
            [Student],
            "A Course", DISTINCTCOUNT ( T3[Course] ),//all courses
            "P Course", CALCULATE ( DISTINCTCOUNT ( T3[Course] ), T3[Result] = "Pass" )//passed courses
        ),
        [A Course] = [P Course]
    )
)

 

Regards,

Xiaoxin Sheng

This is pure witchcraft! Thanks!

Penn
Resolver I
Resolver I

Still no clue

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