March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early bird discount ends December 31.
Register NowBe one of the first to start using Fabric Databases. View on-demand sessions with database experts and the Microsoft product team to learn just how easy it is to get started. Watch now
Hi all,
Here's a very simple example. There are 3 students, and there is a date filter on the report.
Student | Course | Exam Date | Result |
S001 | MBA601 | 1/08/2019 | Fail |
S001 | MCS601 | 5/09/2019 | Pass |
S001 | MBA607 | 7/09/2019 | Pass |
S001 | MBA604 | 9/09/2019 | Pass |
S001 | MBA605 | 21/10/2019 | Pending |
S002 | MCS607 | 7/08/2019 | Fail |
S002 | MBA605 | 8/09/2019 | Pass |
S002 | MBA603 | 23/10/2019 | Pending |
S003 | MCS601 | 5/08/2019 | Pass |
S003 | MBA607 | 7/09/2019 | Pass |
S003 | MCS603 | 7/09/2019 | Pass |
S003 | MBA605 | 8/09/2019 | Pass |
S003 | MBA605 | 9/10/2019 | Pass |
I want to create a measure to count the students passed all courses within a certain time frame.
Say if the date filter in from Aug 2019 to Oct 2019, the result should be 1 as only Student S003 has passed all exams in this time frame. But if I adjust the filter to look at Sep 2019 only, the result should be 3 as all 3 students have passed all exams in September.
The measure that I wrote only works then I put it in a table with [Student] column in it. How can I return the value in a card?
Count All Pass = CALCULATE(DISTINCTCOUNT('Table'[Student]), FILTER(ALLEXCEPT('Table', 'Table'[Student]), AND(MAX('Table'[Result]) = "Pass", MIN('Table'[Result]) = "Pass")))
Solved! Go to Solution.
Hi @Penn ,
You can try to use following measure formula if it suitable for your requirement:
Passed Student Count= COUNTROWS ( FILTER ( SUMMARIZE ( ALLSELECTED ( T3 ), [Student], "A Course", DISTINCTCOUNT ( T3[Course] ),//all courses "P Course", CALCULATE ( DISTINCTCOUNT ( T3[Course] ), T3[Result] = "Pass" )//passed courses ), [A Course] = [P Course] ) )
Regards,
Xiaoxin Sheng
Hi @Penn ,
You can try to use following measure formula if it suitable for your requirement:
Passed Student Count= COUNTROWS ( FILTER ( SUMMARIZE ( ALLSELECTED ( T3 ), [Student], "A Course", DISTINCTCOUNT ( T3[Course] ),//all courses "P Course", CALCULATE ( DISTINCTCOUNT ( T3[Course] ), T3[Result] = "Pass" )//passed courses ), [A Course] = [P Course] ) )
Regards,
Xiaoxin Sheng
This is pure witchcraft! Thanks!
Still no clue
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount!
Your insights matter. That’s why we created a quick survey to learn about your experience finding answers to technical questions.
Arun Ulag shares exciting details about the Microsoft Fabric Conference 2025, which will be held in Las Vegas, NV.
User | Count |
---|---|
124 | |
87 | |
85 | |
70 | |
51 |
User | Count |
---|---|
205 | |
153 | |
97 | |
79 | |
69 |