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NazeefKhan19
Frequent Visitor

Cannot get all dates from a certain date to todays date

I am trying to get dates from an admission date to todays date to go into a custom coumn using the following:

 

{ Number.From([admissionDate])..Number.From(DateTime.Date(DateTime.LocalNow)) } 

 

However the custom column i am adding is coming up with an Error which says :

 

'Expression.Error: The DateTime.Date function expects an input of type DateTime or DateTimeZone.
Details:
[Function]'

 

I thought that DateTime.LocalNow did return the date as of now in a date time format? 

2 ACCEPTED SOLUTIONS
amitchandak
Super User
Super User

Are you looking for datediff or Dates.

In M

=each Duration.Days([Date1] - [Date2])

 

In dax date diff a new column

datediff([admission date],today(),day)

View solution in original post

TomMartens
Super User
Super User

Hey @NazeefKhan19 ,

 

you have to use parenthesis in combination with DateTime.LocalNow as it is a function like so:

Number.From(DateTime.Date(DateTime.LocalNow()))

 

Hopefully, this provides what you are looking for.

 

Regards,

Tom



Did I answer your question? Mark my post as a solution, this will help others!

Proud to be a Super User!
I accept Kudos 😉
Hamburg, Germany

View solution in original post

3 REPLIES 3
TomMartens
Super User
Super User

Hey @NazeefKhan19 ,

 

you have to use parenthesis in combination with DateTime.LocalNow as it is a function like so:

Number.From(DateTime.Date(DateTime.LocalNow()))

 

Hopefully, this provides what you are looking for.

 

Regards,

Tom



Did I answer your question? Mark my post as a solution, this will help others!

Proud to be a Super User!
I accept Kudos 😉
Hamburg, Germany

Hi @TomMartens 

If i am doing the following to get dates between two dates. How do i replace the 'DischargeDate' with today's date if its null?

{ Number.From([AdmissionDate]) ..Number.From([DischargeDate])  }

amitchandak
Super User
Super User

Are you looking for datediff or Dates.

In M

=each Duration.Days([Date1] - [Date2])

 

In dax date diff a new column

datediff([admission date],today(),day)

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