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@PBInonpro , Column will consider the full table and then apply the filter on that, if added. It can not be compared with the measure.
In measure calculate with and without filter will give different result
TestMeasure = CALCULATE(SUMX(plan, plan[REMAINING] * 10), plan[PROJECT] = "OFFICE")
vs
TestMeasure = CALCULATE(SUMX(plan, plan[REMAINING] * 10), FIlter(plan, plan[PROJECT] = "OFFICE"))
will be different
refer: Calculate with and Without filter : https://youtu.be/cN8AO3_vmlY?t=9310
Hi @PBInonpro ,
Your calculated column returns correct result 139500 on myside.
I think 141500 is the sum of the calculated column which is calculated based on your data model. You can try MAX/MIN function on [TestColumn] in table visual and check the result. If you still couldn't find the result, please show us a screenshot of your table or share a sample file with us.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
@PBInonpro , Column will consider the full table and then apply the filter on that, if added. It can not be compared with the measure.
In measure calculate with and without filter will give different result
TestMeasure = CALCULATE(SUMX(plan, plan[REMAINING] * 10), plan[PROJECT] = "OFFICE")
vs
TestMeasure = CALCULATE(SUMX(plan, plan[REMAINING] * 10), FIlter(plan, plan[PROJECT] = "OFFICE"))
will be different
refer: Calculate with and Without filter : https://youtu.be/cN8AO3_vmlY?t=9310
Thanks, but is there a way to see where the 141,500 is coming from on the column?
Hi @PBInonpro ,
Your calculated column returns correct result 139500 on myside.
I think 141500 is the sum of the calculated column which is calculated based on your data model. You can try MAX/MIN function on [TestColumn] in table visual and check the result. If you still couldn't find the result, please show us a screenshot of your table or share a sample file with us.
Best Regards,
Rico Zhou
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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