Forum Discussion
Calculated column - creating partition based on multiple values
- 4 years ago
tomislav_mi , Try a new column like
new column =
var _1 = countx(filter(Table, [Customer] = earlier([Customer]) && [Report Date] = earlier([Report Date]) && [Active Channel] = "Reseller"), [Customer])
var _2 = countx(filter(Table, [Customer] = earlier([Customer]) && [Report Date] = earlier([Report Date]) && [Active Channel] = "Direct"), [Customer])
return
Switch(true(),
not(isblank(_1)) && not(isblank(_2)) , "Both",
not(isblank(_1)),"Reseller",
"Direct"
)
tomislav_mi , Try a new column like
new column =
var _1 = countx(filter(Table, [Customer] = earlier([Customer]) && [Report Date] = earlier([Report Date]) && [Active Channel] = "Reseller"), [Customer])
var _2 = countx(filter(Table, [Customer] = earlier([Customer]) && [Report Date] = earlier([Report Date]) && [Active Channel] = "Direct"), [Customer])
return
Switch(true(),
not(isblank(_1)) && not(isblank(_2)) , "Both",
not(isblank(_1)),"Reseller",
"Direct"
)
amitchandak
Exactly what I was struggling to get! Great approach.
Thank you!