Microsoft is giving away 50,000 FREE Microsoft Certification exam vouchers!
Enter the sweepstakes now!See when key Fabric features will launch and what’s already live, all in one place and always up to date. Explore the new Fabric roadmap
Hi Everyone,
I'm trying to build a table based on 2 existing tables but I need to join to one of the tables using a parameter, I have this code which works from one table:
ClientCodes=SELECTCOLUMNS(FILTER('anallink','anallink'[AG_Type]="C"),"Type",'anallink'[AG_Type],"AC_Code",'anallink'[AC_Code],"PCT",'anallink'[AL_PCT])
I need to bring in another field based on the AL_PCT field, is it possible to do this?
Thanks
Mick
Solved! Go to Solution.
Hi @micklowe ,
According to your description, I made a sample and here is my solution.
I wonder whether I understand your requirement correctly, please follow steps below.
Sample data:
Create a new table as what you wrote.
ClientCodes =
SELECTCOLUMNS (
FILTER ( 'TABLE_A', 'TABLE_A'[AG_TYPE] = "C" ),
"Type", 'TABLE_A'[AG_TYPE],
"AC_CODE", 'TABLE_A'[AC_CODE],
"PCT", 'TABLE_A'[AL_PCT]
)
Then you can establish a relationship between TABLE_B and new table.
Create a calculated column in the new table.
Column =
RELATED ( TABLE_B[OTHER] )
Final output:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ xiaosun
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @micklowe ,
According to your description, I made a sample and here is my solution.
I wonder whether I understand your requirement correctly, please follow steps below.
Sample data:
Create a new table as what you wrote.
ClientCodes =
SELECTCOLUMNS (
FILTER ( 'TABLE_A', 'TABLE_A'[AG_TYPE] = "C" ),
"Type", 'TABLE_A'[AG_TYPE],
"AC_CODE", 'TABLE_A'[AC_CODE],
"PCT", 'TABLE_A'[AL_PCT]
)
Then you can establish a relationship between TABLE_B and new table.
Create a calculated column in the new table.
Column =
RELATED ( TABLE_B[OTHER] )
Final output:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ xiaosun
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
User | Count |
---|---|
91 | |
74 | |
71 | |
58 | |
55 |
User | Count |
---|---|
41 | |
39 | |
34 | |
32 | |
30 |