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Hi Everyone,
I'm trying to build a table based on 2 existing tables but I need to join to one of the tables using a parameter, I have this code which works from one table:
ClientCodes=SELECTCOLUMNS(FILTER('anallink','anallink'[AG_Type]="C"),"Type",'anallink'[AG_Type],"AC_Code",'anallink'[AC_Code],"PCT",'anallink'[AL_PCT])
I need to bring in another field based on the AL_PCT field, is it possible to do this?
Thanks
Mick
Solved! Go to Solution.
Hi @micklowe ,
According to your description, I made a sample and here is my solution.
I wonder whether I understand your requirement correctly, please follow steps below.
Sample data:
Create a new table as what you wrote.
ClientCodes =
SELECTCOLUMNS (
FILTER ( 'TABLE_A', 'TABLE_A'[AG_TYPE] = "C" ),
"Type", 'TABLE_A'[AG_TYPE],
"AC_CODE", 'TABLE_A'[AC_CODE],
"PCT", 'TABLE_A'[AL_PCT]
)
Then you can establish a relationship between TABLE_B and new table.
Create a calculated column in the new table.
Column =
RELATED ( TABLE_B[OTHER] )
Final output:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ xiaosun
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @micklowe ,
According to your description, I made a sample and here is my solution.
I wonder whether I understand your requirement correctly, please follow steps below.
Sample data:
Create a new table as what you wrote.
ClientCodes =
SELECTCOLUMNS (
FILTER ( 'TABLE_A', 'TABLE_A'[AG_TYPE] = "C" ),
"Type", 'TABLE_A'[AG_TYPE],
"AC_CODE", 'TABLE_A'[AC_CODE],
"PCT", 'TABLE_A'[AL_PCT]
)
Then you can establish a relationship between TABLE_B and new table.
Create a calculated column in the new table.
Column =
RELATED ( TABLE_B[OTHER] )
Final output:
I attach my sample below for your reference.
Best Regards,
Community Support Team _ xiaosun
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Your insights matter. That’s why we created a quick survey to learn about your experience finding answers to technical questions.
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