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I have three months value in the table Feb,March,April based on the Attribute Wise .
please find the screen shot below. i am trying to use conditional formatting for the below table.
Can anyone please advise me on this? I am looking for support .
Solved! Go to Solution.
 
					
				
		
Hi @Anonymous ,
Here are the steps you can follow:
1. Use Enter data to create a table Month.
2. In Power query. Add Column – Index Column – From 1.
3. Create calculated column.
Month =
FORMAT('Table'[Date],"mmm")Month_number =
MONTH('Table'[Date])4. Join the two tables.
5. Create measure.
Measure_true =
var _current1=
CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[Month_number]=MAX('Table'[Month_number])-1&&'Table'[Group]=MAX('Table'[Group])))
var _current2=
CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[Month_number]=MAX('Table'[Month_number])&&'Table'[Group]=MAX('Table'[Group])))
return
SWITCH(
    TRUE(),
    _current2>_current1,UNICHAR ( 9650 ),
    _current2<_current1,UNICHAR ( 128315 ),
    _current2=_current1,"=")6. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
 
					
				
		
Hi @Anonymous ,
Here are the steps you can follow:
1. Use Enter data to create a table Month.
2. In Power query. Add Column – Index Column – From 1.
3. Create calculated column.
Month =
FORMAT('Table'[Date],"mmm")Month_number =
MONTH('Table'[Date])4. Join the two tables.
5. Create measure.
Measure_true =
var _current1=
CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[Month_number]=MAX('Table'[Month_number])-1&&'Table'[Group]=MAX('Table'[Group])))
var _current2=
CALCULATE(SUM('Table'[Amount]),FILTER(ALL('Table'),'Table'[Month_number]=MAX('Table'[Month_number])&&'Table'[Group]=MAX('Table'[Group])))
return
SWITCH(
    TRUE(),
    _current2>_current1,UNICHAR ( 9650 ),
    _current2<_current1,UNICHAR ( 128315 ),
    _current2=_current1,"=")6. Result:
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
 
					
				
				
			
		
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