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ub2811's avatar
ub2811
Frequent Visitor
5 years ago
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5 YEARS AVERAGE

Hello there, I hope soemone can help. I have to claulcate a prior 5 years average based on the max date seleted in date slicer i.e If max date selected in slicer is 05/06/2021 then I need mo...
  • Anonymous's avatar
    Anonymous
    5 years ago

    Hi ub2811 ,

     

    Sorry for my late reply.

    Here's my demo you can check.

    1.Create a calendar table.

     

    2.Create a measure.

    5 YEAR AVERAGE = 
    VAR A1 =
        CALCULATE (
            SUM ( 'Date'[Unique Month Number] ),
            FILTER ( 'Date', YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] ) - 1 )
        )
    VAR A2 =
        CALCULATE (
            SUM ( 'Date'[Unique Month Number] ),
            FILTER ( 'Date', YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] ) - 2 )
        )
    VAR A3 =
        CALCULATE (
            SUM ( 'Date'[Unique Month Number] ),
            FILTER ( 'Date', YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] ) - 3 )
        )
    VAR A4 =
        CALCULATE (
            SUM ( 'Date'[Unique Month Number] ),
            FILTER ( 'Date', YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] ) - 4 )
        )
    VAR A5 =
        CALCULATE (
            SUM ( 'Date'[Unique Month Number] ),
            FILTER ( 'Date', YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] ) - 5 )
        )
    VAR BB =
        CALCULATE (
            MAX ( 'Calendar'[Days] ),
            FILTER (
                'Calendar',
                YEAR ( [Date] ) = SELECTEDVALUE ( 'Calendar'[Year] )
                    && [Month] = MONTH ( MAX ( 'Date'[Date] ) )
            )
        )
    RETURN
        DIVIDE (
            DIVIDE ( A1, BB ) + DIVIDE ( A2, BB )
                + DIVIDE ( A3, BB )
                + DIVIDE ( A4, BB )
                + DIVIDE ( A5, BB ),
            5
        )

     

     

    Best Regards,

    Stephen Tao

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.