Forum Discussion
Work Days in Month
Hi, I need a calucation to give me the work day of each month.
Do you have a formula that calculates business days, excluding weekends and holidays?
So, like this year 1/2/24 is working day 1. But I am looking for it to start over each month.
All the examples I have found are total working days for the year. I need for the month. And not total, meaning not 22 days in Jan. I need 1 – 22 detailed out for each month.
Jan 2 = 1
Jan 3 = 2
Jan 4 = 3,
Feb 1 = 1 , etc.
This is what I have right now, but is reserved.
= NETWORKDAYS('Date'[Start Date],'Date'[End Date])
This is results:
Jan 1 = 23
Jan 2 - 22, etc.
Any help ?
Thank you!
Don't waste your time . Use an external table. It's not necessary to calculate this over and over again.
- Anonymous2 years ago
Hi yaya1974 ,
First use this DAX to add a new column:Month = MONTH('Table'[Date])Then please try this DAX to create a new column:
NETWORKDATS = VAR MIN_DAY = CALCULATE( MIN('Table'[Date]), FILTER( 'Table', 'Table'[Month] = EARLIER('Table'[Month]) ) ) VAR MAX_DAY = CALCULATE( MAX('Table'[Date]), FILTER( 'Table', 'Table'[Date] <= EARLIER('Table'[Date]) && 'Table'[Month] = EARLIER('Table'[Month]) ) ) RETURN NETWORKDAYS(MIN_DAY, MAX_DAY)The final output is as below:
Best Regards,
Dino Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- lbendlinSuper User
Don't waste your time . Use an external table. It's not necessary to calculate this over and over again.
- AnonymousNot applicable
Hi yaya1974 ,
First use this DAX to add a new column:Month = MONTH('Table'[Date])Then please try this DAX to create a new column:
NETWORKDATS = VAR MIN_DAY = CALCULATE( MIN('Table'[Date]), FILTER( 'Table', 'Table'[Month] = EARLIER('Table'[Month]) ) ) VAR MAX_DAY = CALCULATE( MAX('Table'[Date]), FILTER( 'Table', 'Table'[Date] <= EARLIER('Table'[Date]) && 'Table'[Month] = EARLIER('Table'[Month]) ) ) RETURN NETWORKDAYS(MIN_DAY, MAX_DAY)The final output is as below:
Best Regards,
Dino Tao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.