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GopVan's avatar
GopVan
Frequent Visitor
3 years ago
Solved

Week Number and ISO Week Number in Power Query

I have added a week number column in Power Query and the output was as follows:

 

26/12/2022 - Week 53

...

31/12/2022 - Week 53

01/01/2023 - Week 1

02/01/2023 - Week 2

 

What is the logic behind this numbering? Why does Week 1 include only Jan 1, 2023?

 

 

How can I generate the ISO Week Number in Power Query (DAX) such that Jan 2, 2023, is Week 1?

7 Replies

  • let
    Source = List.Dates(DateTime.Date(DateTime.LocalNow()), 365, #duration(1, 0, 0, 0)),
    #"Converted to Table" = Table.FromList(Source, Splitter.SplitByNothing(), null, null, ExtraValues.Error),
    #"Renamed Columns" = Table.RenameColumns(#"Converted to Table",{{"Column1", "Date"}}),
    #"Changed Type" = Table.TransformColumnTypes(#"Renamed Columns",{{"Date", type date}}),
    #"Weekday Number" = Table.AddColumn(#"Changed Type", "Weekday Number", each Date.DayOfWeek([Date], Day.Monday)+1),

    #"ISO Week Number" = Table.AddColumn(#"Weekday Number", "ISO Week Number", each if
    Number.RoundDown((Date.DayOfYear([Date])-(Date.DayOfWeek([Date], Day.Monday)+1)+10)/7)=0

    then
    Number.RoundDown((Date.DayOfYear(#date(Date.Year([Date])-1,12,31))-(Date.DayOfWeek(#date(Date.Year([Date])-1,12,31), Day.Monday)+1)+10)/7)

    else if
    (Number.RoundDown((Date.DayOfYear([Date])-(Date.DayOfWeek([Date], Day.Monday)+1)+10)/7)=53
    and (Date.DayOfWeek(#date(Date.Year([Date]),12,31), Day.Monday)+1<4))

    then
    1

    else
    Number.RoundDown((Date.DayOfYear([Date])-(Date.DayOfWeek([Date], Day.Monday)+1)+10)/7))

    in
    #"ISO Week Number"


    GopVan Did I answer your question? Mark my post as a solution! Appreciate your Kudos !!

  • Pepijn's avatar
    Pepijn
    Frequent Visitor

    A shorter formula for ISO-weeks in PBI:

     

    Number.Round((Date.DayOfYear(Date.AddDays([Date],3-Date.DayOfWeek([Date])))-4)/7)+1)

     

    Explanation:

    If the first of january is on a thursday, that is week 1.

    If the first of january is on a friday, that is the last week of last year.

    So... The thursday is always in the right year.

     

    If we grab a random date, and look at the thursday of that week (compensate for the weekday and add 3 to get to thursday)

    We can use the function Date.DayOfYear() to determine the amount of days in the year from that point.

    Then, substract 3 to get to monday, and again 1 to compensate that weekdays start at 0, but DayOfYear starts at 1. (-4 total)

    This, we divide by 7 and round it.

    (if thursday is in the old year, the old year is at least 4 days in that week so it should be rounded down. If thursday is in the new year, the new year is at least 4 days in that week so it should be rounded up)

     

    This method starts 'counting' at 0, so in the end we compensate with a little +1.

  • This is the equivalent to ISOWEEKNUM (or WEEKNUM 21) that worked for me --> Date.DayOfWeek([Date], Day.Thursday)-1