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I am in search of m query that adds a column to display all Children at level 0 in a table with Parent/Child relation. I am already using a function but its painfully slow.
****fnParChAllChildren****
let
Source = (ParChTable as table, ChildKey as text, ParentKey as text) as table =>
let
AllChildren = Table.AddColumn(ParChTable, "AllChildren", each
List.Skip(
List.Generate(()=>
[Children={Record.Field(_, ChildKey)}], // (List of) records as start values
each List.Count([Children]) > 0, // condition under which the next loop is execute
each [ Children= List.Buffer(fnRecColumnAsList(
Table.SelectRows(ParChTable, (ParChTable) => List.Contains([Children], Record.Field(ParChTable, ParentKey)))
, ChildKey))], // Executable action
each [Children]) // (Selection of) return
,1)), // Skip first element in list which is it's own key
LstAllChildren = Table.AddColumn(AllChildren, "LstAllChildren", each List.Combine([AllChildren])),
Level = Table.Buffer(Table.AddColumn(LstAllChildren, "Level", each List.Count([AllChildren]))),
Indent = Table.AddColumn(Level, "Indent", each List.Max(Level[Level])*4-[Level]*4),
JustLevel0 = List.Buffer(fnRecColumnAsList(Table.SelectRows(Indent, each [Level]=0), ChildKey)),
AllChildrenJustLevel0 = Table.AddColumn(Indent, "ChildrenJustLevel0", each List.Intersect({[LstAllChildren], JustLevel0}))
in
AllChildrenJustLevel0
in
Source****fnRecColumnAsList*****
let
Source = (Table as table, ColumnName as text) as list =>
Table.ToColumns(Table.SelectColumns(Table, ColumnName)){0}
in
SourceI forgot where I got it from but it works and I use column AllChildrenJustLevel0 generated by it. Only bad thing is its painfully slow.
Solved! Go to Solution.
I got it to work faster by putting Table.Buffer step just before calling it.
I got it to work faster by putting Table.Buffer step just before calling it.
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