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Hello,
i sure that's is a "basic" problem, but i dont find a solution via Search funtion in this forum.
I'm very new to this topics so please be kind...
I want to filter both Tables for the Place of birth via a relationship by the Identfier.
It works fine for Identfier_new to Identifier relationship - but i also want a query for Identifier_old.
The workflow should be -> if Identifier_new unequal Identifier look for Identifier_old = Identifier.
My Idea was to merge both Columns (Identifier_old & Identifier_new) with Concatenate function.
For the Example : New York - 28479 98323 - unequal 98323 - Susan
Is there a way to define the relationship - "Contains" instead of 1:1 ?
Table 1
| Name | Identifier |
| Charlie | 12345 |
| Susann | 98323 |
Table 2
| Place of birth | Identifier_new | Identifier_old |
| New Jersey | 12345 | XALOE |
| New York | 28479 | 98323 |
Solved! Go to Solution.
Hi @Florex ,
Please have a try.
Create relationship beweet the tables.
Then create a measure.
Measure = MAX(Table2[Place of birth]) &"-"& MAX(Table2[Identifier_new])&" "&MAX(Table2[Identifier_old])&"- unequal" &" "&MAX(Table1[Name])&" "&MAX(Table1[Identifier])
How to Get Your Question Answered Quickly - Microsoft Fabric Community
If it does not help, please provide more details with your desired output and pbix file without privacy information (or some sample data) .
Best Regards
Community Support Team _ Rongtie
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Florex ,
Please have a try.
Create relationship beweet the tables.
Then create a measure.
Measure = MAX(Table2[Place of birth]) &"-"& MAX(Table2[Identifier_new])&" "&MAX(Table2[Identifier_old])&"- unequal" &" "&MAX(Table1[Name])&" "&MAX(Table1[Identifier])
How to Get Your Question Answered Quickly - Microsoft Fabric Community
If it does not help, please provide more details with your desired output and pbix file without privacy information (or some sample data) .
Best Regards
Community Support Team _ Rongtie
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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