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incremental column in Power BI

Hi Folks, I need small help. How to add incremental column in power bi, my source is tabular model i need add one column to display 1 to 50.

Note: Without using Rank and without touching my model i need to display 1 To 50 number sort by paid amount.

incremental column.PNG

Community Support
Community Support

Hi @Anonymous ,

If you don't want to use Rank(), you can try this:

1. Sort the Paid Amount column by DESC in power query editor

sort desc.png

2. Create an index column start from 1:


3. Close and apply power query editor, put this index column into the table to get the number 1-50 which is sorted by Paid Amount column

table index.png

Best Regards,
Yingjie Li

If this post helps then please consider Accept it as the solution to help the other members find it more quickly.

Not applicable

Hi v-yingjl, Thanks for your reply this is really helpful when we have an source like SQL OR Exel or any other source but here my scenario is  my source is tabular model so i can't create index column inpower Bi desktop level, If you have any other ways to add an cremental columns please suggest me.

Hi @Anonymous ,

Now let's arrange it together. Since your data source is a tabular model so that you cannot create a calculate column using Rankx(). Also, you don't want to modify your model. Right?

If so, whether I can create a measure intersperseding rankx() in it like this with the tabular model in power bi desktop to meet your requirement:

Measure =
VAR tab =
        Sheet1[Provider Legacy Number],
        Sheet1[Paid Amount],
        "Rank", RANKX ( ALL ( Sheet1 ), Sheet1[Paid Amount] )
    SUMX ( tab, [Rank] )

tabular table.png

Best Regards,
Yingjie Li

If this post helps then please consider Accept it as the solution to help the other members find it more quickly.


Not applicable

Hi still am getiing issue becacuse Sheet1[Paid Amount],  this is calucalted measure in model  while writing  measure am not able to get paidamount . In my report all columns are coming from different table.

Super User
Super User

@Anonymous you can use rank function, see here


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