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Frequent Visitor

## format field

Hello,

I have one column which contains version of softwares like below

3.1.7.12

3.1.7.14

2.6.5

2.6.8

27.4.12.8

and so on...

My question is how can I format each numbers between two points to have every time 2 digits ? So:

03.01.07.12

03.01.07.14

02.06.05

02.06.08

27.04.12.08

Is it possible to do that with dax formulas ?

Sébastien

2 ACCEPTED SOLUTIONS
Employee

Hi @Hussard,

Based on my test, you could refer to below steps:

Sample data:

Create 5 columns:

`B = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1))<2,"0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1),PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1)))`
`C = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2),PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2)))`
`D = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3),"."&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3)))`
`E = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4),"."&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4)))`
`New A = Table2[B]&Table2[C]&Table2[D]&Table2[E]`

Result :

Regards,

Daniel He

Community Support Team _ Daniel He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Anonymous
Not applicable

Hi @Hussard

The following way you can get your solution easily.

1. Go to the Edit Query option under the ribbon pallet.
2. Create a duplicate column from the existing column.
3. Go to the Transform tab in Query editor and Select Split column By Delimeter within drop-down select Delimiter type as a "Custom Delimiter" and put "." in the box, then select Each occurrence of Delimeter under "Split at" option.
4. Change the type of each Delimited column.
5. Calculate the length of each Delimited column.
6. Choose the Custom column option under the Add column option and write the below code.
7. (if [FstPart Length]=1 then ("0" & [FstPart]) else [FstPart]) &
(if [FstPart Length]=0 then "" else ".") &
(if [SecPart Length]=1 then ("0" & [SecPart]) else [SecPart]) &
(if [SecPart Length]=0 then "" else ".") &
(if [ThrdPart Length]=1 then ("0" & [ThrdPart]) else [ThrdPart]) &
(if [FrthPart Length]=0 then "" else ".") &
(if [FrthPart Length]=1 then ("0" & [FrthPart]) else [FrthPart])
8. Then Select "close & Apply" under the Home tab.

I have given the Sample Pbix file link below. Hope this helps you.

3 REPLIES 3
Anonymous
Not applicable

Hi @Hussard

The following way you can get your solution easily.

1. Go to the Edit Query option under the ribbon pallet.
2. Create a duplicate column from the existing column.
3. Go to the Transform tab in Query editor and Select Split column By Delimeter within drop-down select Delimiter type as a "Custom Delimiter" and put "." in the box, then select Each occurrence of Delimeter under "Split at" option.
4. Change the type of each Delimited column.
5. Calculate the length of each Delimited column.
6. Choose the Custom column option under the Add column option and write the below code.
7. (if [FstPart Length]=1 then ("0" & [FstPart]) else [FstPart]) &
(if [FstPart Length]=0 then "" else ".") &
(if [SecPart Length]=1 then ("0" & [SecPart]) else [SecPart]) &
(if [SecPart Length]=0 then "" else ".") &
(if [ThrdPart Length]=1 then ("0" & [ThrdPart]) else [ThrdPart]) &
(if [FrthPart Length]=0 then "" else ".") &
(if [FrthPart Length]=1 then ("0" & [FrthPart]) else [FrthPart])
8. Then Select "close & Apply" under the Home tab.

I have given the Sample Pbix file link below. Hope this helps you.

Frequent Visitor

Hi both,

Thanks a lot I tried both solutions and it suits me.

Regards

Sébastien

Employee

Hi @Hussard,

Based on my test, you could refer to below steps:

Sample data:

Create 5 columns:

`B = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1))<2,"0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1),PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 1)))`
`C = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2),PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 2)))`
`D = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3),"."&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 3)))`
`E = IF(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4)=BLANK(),BLANK(),IF(LEN(PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4))<2,".0"&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4),"."&PATHITEM(SUBSTITUTE('Table2'[A],".", "|"), 4)))`
`New A = Table2[B]&Table2[C]&Table2[D]&Table2[E]`

Result :

Regards,

Daniel He

Community Support Team _ Daniel He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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