Forum Discussion
extract rows in table based on other table
I have two tables. One table exist the names of rows i want to execute in the second table.
How can I do that?
This column names need to be executed in this table:
Hi GTheunissen ,
So you want to filter the second table for usernames that are common to the first table?
If so, you can try this measure to filter:
Measure = IF(SELECTEDVALUE('Table 1'[username]) in VALUES('Table 2'[Column2]),SELECTEDVALUE('Table 2'[Column2]))the result will as the image shows:
If this way meets your needs, you also can view my testing pbix file.
Best regards,
Community Support Team Selina zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
5 Replies
Samarth_18Community Champion
Hi GTheunissen ,
Your question is not much clear. Could you please explain with examples and also share your sample data in text format not a screenshot.
Note:- One suggestion kindly promote your first row as a header in table 2 as shown below:-
BR,
Samarth
- Jeanxyz
Power Participant
If you want to filter table 1 based on the companies that exist in table 2, you can merge tables in Power Query.
step 1. Merge table1 and 2 based on company name
step2. expand company name column from table 2
step 3. export the merged table3
There are different ways to export the data, here I simply copy the whole table3 and paste it to Excel. You can filter out the null values in tab2: Company Name before copy data.
- tamerj1
Hi GTheunissen
There must be a column that links table1 with table2
- Jeanxyz
yes, table 1 merges with tab2 based on column company name.
Hi GTheunissen ,
So you want to filter the second table for usernames that are common to the first table?
If so, you can try this measure to filter:
Measure = IF(SELECTEDVALUE('Table 1'[username]) in VALUES('Table 2'[Column2]),SELECTEDVALUE('Table 2'[Column2]))the result will as the image shows:
If this way meets your needs, you also can view my testing pbix file.
Best regards,
Community Support Team Selina zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
