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KOLD1313's avatar
KOLD1313
New Member
1 year ago
Solved

UCL calculations limits and graph

Hello,

I am new to powerBi and I need to create a upper control limit that is generated base on the las 15 months data using 2 sigmas (UCL= overall average + 2sigma). The data I have is from different product and some mothns I dont record any values (see image below).  I want to use a slicer to be able to differenciate products.

  • Anonymous's avatar
    Anonymous
    1 year ago

    Hi KOLD1313 ,

    Based on the testing, please try the following methods:

    1.Create the sample table.

    2.Create the new measure to calculate average.

    Average Rate = 
    CALCULATE(
        AVERAGE('Table'[Rejects rate]),
        DATESINPERIOD('Table'[Date], MAX('Table'[Date]), -15, MONTH)
    )

    3.Create the new measure to calculate the std.

    Std Rate = 
    CALCULATE(
        STDEV.P('Table'[Rejects rate]),
        DATESINPERIOD('Table'[Date], MAX('Table'[Date]), -15, MONTH)
    )

    4.Create the measure to calculate the ucl.

    UCL Rate = 
    [Average Rate] + 2 * [Std Rate]

    5.The result is shown below.

     

    Best Regards,

    Wisdom Wu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi KOLD1313 ,

    Based on the testing, please try the following methods:

    1.Create the sample table.

    2.Create the new measure to calculate average.

    Average Rate = 
    CALCULATE(
        AVERAGE('Table'[Rejects rate]),
        DATESINPERIOD('Table'[Date], MAX('Table'[Date]), -15, MONTH)
    )

    3.Create the new measure to calculate the std.

    Std Rate = 
    CALCULATE(
        STDEV.P('Table'[Rejects rate]),
        DATESINPERIOD('Table'[Date], MAX('Table'[Date]), -15, MONTH)
    )

    4.Create the measure to calculate the ucl.

    UCL Rate = 
    [Average Rate] + 2 * [Std Rate]

    5.The result is shown below.

     

    Best Regards,

    Wisdom Wu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.