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Anonymous's avatar
Anonymous
Not applicable
5 years ago
Solved

Sumx with filter over another Table

Hi All

 

I am exactly requiring what microsoft is showing in below example:

https://docs.microsoft.com/en-us/dax/sumx-function-dax

 

The only differnece is that I need the filter from table "Lian CH$Item" and the summerize is for the Table Lian CH$Sales Invoice Line

 

 

However, I noticed that I only can use measures for the sumx but not Quantity as I would like:

 

But this is giving me an Error.

DAX:

Turnover OTC (Number) Spread orders current year vs. last year (Number) = SUMx(FILTER('Lian CH$Item','Lian CH$Item'[Item Group Code] = "A-Liste-C"),'Lian CH$Sales Invoice Line'[Quantity])

 

 

any Idea what I am doing wrong?

 

I would like to have for each customer the total of ammount ordered.

 

Need Help
  • amitchandak's avatar
    amitchandak
    5 years ago

    Anonymous , Try like

     

    Turnover OTC (Number) Spread orders current year vs. last year (Number) = CALCUALTE(SUM('Lian CH$Sales Invoice Line'[Quantity]),FILTER('Lian CH$Item','Lian CH$Item'[Item Group Code] = "A-Liste-C"))

2 Replies

  • amitchandak's avatar
    amitchandak
    Super User
    5 years ago

    Anonymous , Try like

     

    Turnover OTC (Number) Spread orders current year vs. last year (Number) = CALCUALTE(SUM('Lian CH$Sales Invoice Line'[Quantity]),FILTER('Lian CH$Item','Lian CH$Item'[Item Group Code] = "A-Liste-C"))

  • Anonymous's avatar
    Anonymous
    Not applicable
    5 years ago

    Hi  Anonymous  ,

    According to your description, I create some data:

    Table:

    Table2:

    Here are the steps you can follow：

    The column of the second parameter of Sumx must come from the table in the first parameter. You can also use the RELATED() function to pull the column of another table

    1. Create calculated column.

    Column =
SUMX(FILTER('Table','Table'[group]="A"),RELATED('Table (2)'[value]))

    2. Result.

    You can downloaded PBIX file from here.

     

    Best Regards,

    Liu Yang

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.