The ultimate Fabric, Power BI, SQL, and AI community-led learning event. Save €200 with code FABCOMM.
Get registeredCompete to become Power BI Data Viz World Champion! First round ends August 18th. Get started.
Good afternoon everyone,
I am trying to figure out a way to accurately show how many times an installer had an installation. The problem that i am running into though is that the column of information that records who the installer was can sometimes contain multiple installers (if there were multiple installers present). I have 2 tables, one with the orders and one with the list of possible installers. So for example my data may look like:
Base Data
Order | Installer |
1234 | Joe A |
5678 | Jim B,Joe A |
9012 | Jim B,Joe A,Frank R |
Technicians
Installer |
Joe A |
Jim B |
Frank R |
I've tried using a measure that contains the following:
Installer Instances = SUMX( BaseData, IF( CONTAINSSTRING(BaseData[Installer], SELECTEDVALUE(Technicians[Installer])), 1,0 ) )
Unfortunately that doesn't seem to find names if there are multiple per cell. Any ideas, i'm kinda stumped?
Thanks in advance!
Solved! Go to Solution.
I think i figured out a solution myself.
I took a big step back and instead just split the data in that column to create multiple rows. Once i changed the relationship data it seemed to be happy.
Not sure why that formula wouldn't work for me, but thank you for the help all the same!
@Anonymous
What is your expected result in above case?
My hope is that if i reduce the number of displayed orders, via a slicer based on date, that i can show the correct totals for the number of times installers have been deployed.
So, in the data set that i provided my numbers would be
Joe A. - 3
Jim B. - 2
Frank R. - 1
I would then display that result via a bar graph.
@Anonymous
I tested your formula and it gives the stated results.
Am i missing something?
I think i figured out a solution myself.
I took a big step back and instead just split the data in that column to create multiple rows. Once i changed the relationship data it seemed to be happy.
Not sure why that formula wouldn't work for me, but thank you for the help all the same!