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Crav888
Frequent Visitor

Sum Multiple when filtered

Hi, 

 

I have the following data set:

 

Area  Item  Cost      

1        Yes    5

1        Yes    10

1        No    20

2        No    12 

2        Yes    13 

2        Yes     12

 

How do I achieve the following:

Sum of cost where Item is "yes" divided by Sum of cost with both "yes" and "no"?

 

It should be so easy, but I am afraid I simply can't crack it, and it is rather urgent.

 

Thank you in advance,

And happy holidays 😄

1 ACCEPTED SOLUTION
Ashish_Mathur
Super User
Super User

Hi,

 

Try this

 

=CALCULATE(SUM(Data[Cost]),Data[Item]="Yes")/SUM(Data[Cost])

 

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

View solution in original post

3 REPLIES 3
v-jiascu-msft
Microsoft Employee
Microsoft Employee

Hi @Crav888,

 

Another try:

Measure =
CALCULATE ( SUM ( 'table3'[Cost] ), 'table3'[Item] = "Yes" )
    / CALCULATE ( SUM ( table3[Cost] ), ALL ( table3[Item] ) )

Best Regards,

Dale

Community Support Team _ Dale
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Ashish_Mathur
Super User
Super User

Hi,

 

Try this

 

=CALCULATE(SUM(Data[Cost]),Data[Item]="Yes")/SUM(Data[Cost])

 

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
mehaboob557
Resolver III
Resolver III

Hi @Crav888,

 

You have to create Measure with FIlter then like below,

 

Measure Sum of Yes = CALCULATE(SUMX(Table3,Table3[Cost]),FILTER(Table3,Table3[Item]="YES"))

Measure Sum of NO = CALCULATE(SUMX(Table3,Table3[Cost]),FILTER(Table3,Table3[Item]="NO"))



Divide measure = ([Measure Sum of Yes]/([Measure Sum of Yes]+[
Measure Sum of NO]))

If it works, Please Like(kudo) my answer and accept as solution.

 

Regard,

Mehbub

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