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Anonymous
Not applicable

Split columns by DAX with varying length per row

Hi,

I have a table and one of the column have many values delimited by comma as below:

weekIDName
W401002abcde,abc,abcd,abcdef
W401001abcde,fgh
W402001ijk
W402002

ijk,lmn,opeqrs


I want to split the name by comma, also keep the detail of them.
Length of name might be different, and the name is too much to use exhaustive way.

The output I expected as below:

weekIDName
W401002abcde
W401002abc
W401002abcd
W401002abcdef
W401001abcde
W401001fgh
W402001ijk
W402002ijk
W402002lmn
W402002lmn,opeqrs


I can use DAX only. (can't use power query)
Any answer will be helpful!

1 ACCEPTED SOLUTION
bhanu_gautam
Super User
Super User

@Anonymous , Create a new calculated table by going into Modelling

 

SplitNamesTable =
ADDCOLUMNS(
    GENERATE(
        'OriginalTable',
        VAR NameList = SUBSTITUTE('OriginalTable'[Name], ",", "|")
        VAR NameCount = PATHLENGTH(NameList)
        RETURN
            SELECTCOLUMNS(
                GENERATESERIES(1, NameCount),
                "week", 'OriginalTable'[week],
                "ID", 'OriginalTable'[ID],
                "Name", PATHITEM(NameList, [Value], TEXT)
            )
    ),
    "Name", SUBSTITUTE([Name], "|", ",")
)



Did I answer your question? Mark my post as a solution! And Kudos are appreciated

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2 REPLIES 2
bhanu_gautam
Super User
Super User

@Anonymous , Create a new calculated table by going into Modelling

 

SplitNamesTable =
ADDCOLUMNS(
    GENERATE(
        'OriginalTable',
        VAR NameList = SUBSTITUTE('OriginalTable'[Name], ",", "|")
        VAR NameCount = PATHLENGTH(NameList)
        RETURN
            SELECTCOLUMNS(
                GENERATESERIES(1, NameCount),
                "week", 'OriginalTable'[week],
                "ID", 'OriginalTable'[ID],
                "Name", PATHITEM(NameList, [Value], TEXT)
            )
    ),
    "Name", SUBSTITUTE([Name], "|", ",")
)



Did I answer your question? Mark my post as a solution! And Kudos are appreciated

Proud to be a Super User!




LinkedIn






Anonymous
Not applicable

This is exactly what I need!! Thank you for your reply!!

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