Forum Discussion

Syndicate_Admin's avatar
Syndicate_Admin
Administrator
5 years ago
Solved

Set actual date based on time

Hello good day.

I have a database where I have date, code, time of realization, etc..

BereniceMtz10_1-1628187144931.png

I'm doing a count of how many activities a person does per month in a company.

The problem is that according to the schedule is the date, that is, from 6:00 am to 5:59 am that activity if it belongs to that day, after 6:00 am it would enter the next day. Which is not a problem until the end of the month.

That is, if a person charges an activity on July 1 at 5:00 am or 5:59 am should not count it in July, but in June.

What formula would it have to occupy for the correct date to count? I was trying to test by making a calculated table.

with the following formula:

Real Date = IF('Historical Inspections'[Time] < "6:00 a.m.", 'Historical Inspections'[Date], 'Historical Inspections'[Date] -1)
but I get error by the date type and Text type values.
I don't think it would be right to do this, I hope you can help me.
Thank you
  • amitchandak's avatar
    amitchandak
    5 years ago

    Syndicate_Admin , make sure time is time datatype and then try

    Real Date = IF('Historical Inspections'[Time] < time(6,0,0) , 'Historical Inspections'[Date], 'Historical Inspections'[Date] -1)

     

    but I think this needs to be

     

    Real Date = IF('Historical Inspections'[Time] >= time(6,0,0) , 'Historical Inspections'[Date], 'Historical Inspections'[Date] -1)

1 Reply

  • amitchandak's avatar
    amitchandak
    Super User
    5 years ago

    Syndicate_Admin , make sure time is time datatype and then try

    Real Date = IF('Historical Inspections'[Time] < time(6,0,0) , 'Historical Inspections'[Date], 'Historical Inspections'[Date] -1)

     

    but I think this needs to be

     

    Real Date = IF('Historical Inspections'[Time] >= time(6,0,0) , 'Historical Inspections'[Date], 'Historical Inspections'[Date] -1)