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thampton
Helper III
Helper III

Running Total By Month on Date Table

Hello - I have seen many answers to this questions but none seem to work in my situation. I have a date table (date, day, month, etc) and a column showing business days. I would like to have a MTD business days calculation that is a running total up to the current day and starting over at the beginning of each month. Should

 

Date          Business Days    Running Total
Jan 1                   1                     1

Jan 2                   1                     2

Jan 3                   1                     3

....

Feb 1                   1                     1

 

 

Any thoughts?

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi  @thampton  ,

According to your description, I create this data from 2021.1.1-2021.2.28:

v-yangliu-msft_0-1614317097740.png

Here are the steps you can follow:

1. Create calculated table.

Business Day =
var _weekday=WEEKDAY('Table'[date])
return
IF(OR(_weekday=6,_weekday=7),0,1)
running total =
CALCULATE(SUM('Table'[Business Day]),FILTER('Table','Table'[Business Day]=1&&'Table'[Month]=EARLIER('Table'[Month])&&'Table'[date]<=TODAY()))

2. Result.

v-yangliu-msft_1-1614317097745.png


You can downloaded PBIX file from here.

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
Anonymous
Not applicable

Hi  @thampton  ,

According to your description, I create this data from 2021.1.1-2021.2.28:

v-yangliu-msft_0-1614317097740.png

Here are the steps you can follow:

1. Create calculated table.

Business Day =
var _weekday=WEEKDAY('Table'[date])
return
IF(OR(_weekday=6,_weekday=7),0,1)
running total =
CALCULATE(SUM('Table'[Business Day]),FILTER('Table','Table'[Business Day]=1&&'Table'[Month]=EARLIER('Table'[Month])&&'Table'[date]<=TODAY()))

2. Result.

v-yangliu-msft_1-1614317097745.png


You can downloaded PBIX file from here.

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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