Forum Discussion
Return a unique value by counting specific values under multiple criterias
Hello all,
I am trying to return a unique number (this is important, because i know how to get that number through a table visual, but not as a single value) based on specific criterias : i need the number of agencies that have placed multiple orders in a day.
Something like "distinctcount agency if number of orders in one day >1"
I have the following table :
DATEVE = Date
NUMEVE = Order ID
Cle_Liv = Agency ID
The idea would be to do a Group By, but i will need to the same type of calculations in this table with different criterias, and i do not wish to add "who knows" amount of new tables everytime.
I would also like to keep as much details as possible (like the order ID for example), so I am avoiding the "Group By".
Instead i tried to get a calculated column that would return "Yes" if the line is considered "Multiple" or "No" if not.
Something like this :
I could then create simple measure to deduce what i need.
I was thinking, maybe i could count the duplicate values on dates or agency, but i didn't manage to do both within a single calculation. I tried the following :
I am a bit stuck on this one.
I am open to any solution. If i was not clear in my question, please do say so π
The answer might be obvious for some of you, so your wisdom would be appreciated for a novice !
Hi mariuscourcel ,
Do you mean to get the "Test" formula? Try to add "Date" condition.
Test = IF ( COUNTROWS ( FILTER ( Bd_03_Franco; Bd_03_Franco[Cle_Liv] = EARLIER ( Bd_03_Franco[Cle_Liv] ) && Bd_03_Franco[Date] = EARLIER ( Bd_03_Franco[Date] ) ) ) > 1; 1; BLANK () )
2 Replies
- v-eachen-msftCommunity Support
Hi mariuscourcel ,
Do you mean to get the "Test" formula? Try to add "Date" condition.
Test = IF ( COUNTROWS ( FILTER ( Bd_03_Franco; Bd_03_Franco[Cle_Liv] = EARLIER ( Bd_03_Franco[Cle_Liv] ) && Bd_03_Franco[Date] = EARLIER ( Bd_03_Franco[Date] ) ) ) > 1; 1; BLANK () )- mariuscourcelFrequent Visitor
Yes, that's the idea.
It does work for my problem, although this might not be the best way to do it. If you have any other way, just has a way of learning more, please do share.
I will accept this as answer.
Thank you !