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Hi Everyone!
I have a data table like that:
| ID | HOURS | DATE | NAME |
| TLIONINOX-42 | 4 | 2016-10-10 | Jhon |
| TBROEMBPT-8 | 5 | 2016-10-10 | Mike |
| TRSSHAREPO-27 | 8,5 | 2016-11-9 | Louis |
| TOFREBOOT-51 | 3 | 2016-10-10 | Jhon |
| TMNTOF-767 | 2 | 2016-11-10 | Mike |
| TPINEIROEC-19 | 7 | 2016-11-10 | Louis |
| TMNTOF-809 | 1 | 2016-11-10 | Jhon |
I would like to add a new column with the % of work ocupation per month for every person.
Ocupation_% = HOURS/SUM(HOURS of this person on this month)
Something like this:
| ID | HOURS | DATE | NAME | OCUPATION_% |
| TLIONINOX-42 | 4 | 2016-10-10 | Jhon | 57% |
| TBROEMBPT-8 | 5 | 2016-10-10 | Mike | 100% |
| TRSSHAREPO-27 | 8,5 | 2016-11-9 | Louis | 55% |
| TOFREBOOT-51 | 3 | 2016-10-10 | Jhon | 43% |
| TMNTOF-767 | 2 | 2016-11-10 | Mike | 100% |
| TPINEIROEC-19 | 7 | 2016-11-10 | Louis | 45% |
| TMNTOF-809 | 1 | 2016-11-10 | Jhon | 100% |
I can't find the formula to do this to me.
Some help please....
Solved! Go to Solution.
This should work as a Column and a Measure
FORMULA =
DIVIDE (
CALCULATE ( SUM ( 'Table'[HOURS] ) ),
CALCULATE (
SUM ( 'Table'[HOURS] ),
ALLEXCEPT ( 'Table', 'Table'[NAME], Table[DATE].[Month] )
),
0
)
This should work as a Column and a Measure
FORMULA =
DIVIDE (
CALCULATE ( SUM ( 'Table'[HOURS] ) ),
CALCULATE (
SUM ( 'Table'[HOURS] ),
ALLEXCEPT ( 'Table', 'Table'[NAME], Table[DATE].[Month] )
),
0
)
Thanks for the solution @Sean.
It works fine, although the decimals don't adjust perfectly to 100% of the total, 1-2% above sometimes. But in general looks good.
Thanks!
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