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Anonymous
Not applicable

On Time and In Full Overlap Calculation

Hi All,

 

I know this should be a relatively easy calculation, but I am struggling on sorting out the DAX for it.

 

I have a table that tracks shipments. I have one column that indicates if a shipment left our building "On Time" or not. Y or N values.

I have a second column that indicates if the orders was shipped in full or not. Y or N values as well. Example:

 

Canknucklehead_0-1629469226010.png

 

I have created measures to provide me the totals. IE On Time = 4500, Late = 1200, In Full =4000 and Short Ship = 1700. Total shipments = 5700

 

I'm trying to figure out how to calculate the total number of shipments that were both On Time and In Full. I'm struggling on what the DAX should be in order to count the overlaps and then divide by the total to get the percentage. 

 

1 ACCEPTED SOLUTION
richbenmintz
Resident Rockstar
Resident Rockstar

Hi @Anonymous ,

 

Pretty sure something like

% of On Time Filled =
var _on_time_in_full = Calculate(countrows('shipment table'), filter('shipment table', 'shipment table'[on_time] = 'Y' && 'shipment table'[on_time] = 'Y'))
var _all = countrows('shipment table'))
return 
divide (_on_time_in_full, _all)

would work for you.

 

Hope this Helps 



I hope this helps,
Richard

Did I answer your question? Mark my post as a solution! Kudos Appreciated!

Proud to be a Super User!


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3 REPLIES 3
parry2k
Super User
Super User

@Anonymous try this measure:

 

ON Time and Full = 
CALCULATE ( COUNRTOWS ( ShipmentTable ), 
    ShipmentTable[OnTime] = "Y",
    ShipmentTable[ShippedFull] = "Y"
)

 

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richbenmintz
Resident Rockstar
Resident Rockstar

Hi @Anonymous ,

 

Pretty sure something like

% of On Time Filled =
var _on_time_in_full = Calculate(countrows('shipment table'), filter('shipment table', 'shipment table'[on_time] = 'Y' && 'shipment table'[on_time] = 'Y'))
var _all = countrows('shipment table'))
return 
divide (_on_time_in_full, _all)

would work for you.

 

Hope this Helps 



I hope this helps,
Richard

Did I answer your question? Mark my post as a solution! Kudos Appreciated!

Proud to be a Super User!


Anonymous
Not applicable

That's the one! Thank you!

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