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Hello everyone,
I have a problem: I have a table that contains over 70 columns and over 10000 records.
My goal is to get a dashboard where I can filter by object name and display which columns are filled out for this object and what information is contained there.
I also want to display which columns are not filled out and preferably also display their amount.
For example:
| Name | Data 1 | Data 2 | Data 3 |
| a | 1 | 4 | |
| b | 2 | 3 | |
| c | 3 | 1 | 4 |
| d | 2 |
If I filter by "a" I want to see something like this as a result:
| Name | Filled columns | Value | Amount of unfilled columns | Unfilled columns |
| a | Data 1 | 1 | 1 | Data 3 |
| Data 2 | 4 |
Not everything has to be displayed in a table, those could just as well be different visual elements.
How could this be solved?
Thank you for your help!
Solved! Go to Solution.
Hi @mmv ,
Based on the data you provide, you can do the following:
Unpbviot the data column
Create a table
Table 2 = VALUES('Table'[Attribute])
Create relationship
Create measures
Amount of unfilled columns =
VAR allCount =
CALCULATE(
DISTINCTCOUNT('Table'[Attribute]),
REMOVEFILTERS('Table'[Name])
)
VAR selected = DISTINCTCOUNT('Table'[Attribute])
RETURN
allCount - selectedMeasure =
IF(
SELECTEDVALUE('Table'[Attribute]) IN VALUES('Table 2'[Attribute]),
1,
0
)
Create matrix
Create a table using table2 and apply a filter
Final output
Best regards,
Albert He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
Hi @mmv ,
Based on the data you provide, you can do the following:
Unpbviot the data column
Create a table
Table 2 = VALUES('Table'[Attribute])
Create relationship
Create measures
Amount of unfilled columns =
VAR allCount =
CALCULATE(
DISTINCTCOUNT('Table'[Attribute]),
REMOVEFILTERS('Table'[Name])
)
VAR selected = DISTINCTCOUNT('Table'[Attribute])
RETURN
allCount - selectedMeasure =
IF(
SELECTEDVALUE('Table'[Attribute]) IN VALUES('Table 2'[Attribute]),
1,
0
)
Create matrix
Create a table using table2 and apply a filter
Final output
Best regards,
Albert He
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly
Hello @mmv , and thank you for sharing a question with the Community. This reply is informational. Please remember to adhere to the decorum of the Community Forum when asking a question.
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