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Hello Power BI experts 🙂
I ran into a problem, seems easy, but I can't figure it out.
I am creating a new column, a simple SUM (from another column), but I only want this sum to appear only on the row with a specific ID.
Heres is an example.
Let's say that I want to SUM a certain column from Table 2, and I only want it to appear in Table 1 when ID =2
My table 1:
ID Column I need
1
2 SUM('Table2'[Column])
3
4
Does anyone know how to do this?
I tried doing a calculate and then filter it to this specific ID but it returns with errors.
Thank you for your help 🙂
Solved! Go to Solution.
Hi @Anonymous ,
You can do like this.
1. Create a column in Table2.
Column =
CALCULATE(
SUM(Table2[Value]),
FILTER(
Table2,
Table2[ID] = EARLIER( Table2[ID]) && Table2[ID] = 2
)
)
2. Create a column in Table 1.
Column =
LOOKUPVALUE(
Table2[Column],
Table2[ID], Table1[ID]
)
Best regards,
Lionel Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @Anonymous ,
You can do like this.
1. Create a column in Table2.
Column =
CALCULATE(
SUM(Table2[Value]),
FILTER(
Table2,
Table2[ID] = EARLIER( Table2[ID]) && Table2[ID] = 2
)
)
2. Create a column in Table 1.
Column =
LOOKUPVALUE(
Table2[Column],
Table2[ID], Table1[ID]
)
Best regards,
Lionel Chen
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
@Anonymous , try like
if there is a join
new column = sum(RELATED('Table2'[Column]))
wthout using related
new column = sumx(FILTER(table2,table2[Id]=table1[ID] && table2[Id]=2),'Table2'[Column])
You can change the filter condition as per need
Hi @Anonymous
You can indeed use the calculate function here.
The Column would look like this:
Column =
VAR CurrentID = 'Table1'[ID]
RETURN
CALCULATE (
SUM ( 'table2'[column] ),
FILTER ( table2, 'table2'[ID] = CurrentID )
)
Hope it helps,
Kind regards
Joren Venema
Data & Analytics Consultant
If this reply solved your question be sure to mark this post as the solution to help others find the answer more easily.
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