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alesmarcioni
Frequent Visitor

Need Help - Measure (Basic)

Hi everybody, I'm Alessandro, a new user in this forum. It is really nice to meet you!

I started using Power B.I. just this week and, !wow!, it is a really great tool!

I need a (i think basic) help for create a new measure because i don't understand how to make a simple multiplication. 

I've got 2 tables (which have a join on ItemID).

 

TABLE A: ItemID, cost

TABLE B: SerialNumber(univ.), ItemID, Qty

 

For every SerialNumber i have to make (TABLE A).cost * (TABLE B).Qty

In SQL it is an easy operation, but i can't get this in Power BI.

Can anyone explain me any step to make this measure?

 

Thank you so mutch for the help!

 

 

1 ACCEPTED SOLUTION
OwenAuger
Super User
Super User

Hi Alessandro,

 

Welcome to the forum 🙂

 

In this situation, you can use SUMX to iterate over the rows of 'TABLE A' and multiply each row's cost by the sum of Qty for the corresponding rows in 'TABLE B'.

In fact you can iterate over the distinct values of 'TABLE A'[cost] rather than each row of 'TABLE A':

 

=
SUMX (
    VALUES ( 'TABLE A'[cost] ),
    'TABLE A'[cost] * CALCULATE ( SUM ( 'TABLE B'[Qty] ) )
)

Does a measure like this give you the result you expect?

 

Regards,

Owen


Owen Auger
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View solution in original post

2 REPLIES 2
OwenAuger
Super User
Super User

Hi Alessandro,

 

Welcome to the forum 🙂

 

In this situation, you can use SUMX to iterate over the rows of 'TABLE A' and multiply each row's cost by the sum of Qty for the corresponding rows in 'TABLE B'.

In fact you can iterate over the distinct values of 'TABLE A'[cost] rather than each row of 'TABLE A':

 

=
SUMX (
    VALUES ( 'TABLE A'[cost] ),
    'TABLE A'[cost] * CALCULATE ( SUM ( 'TABLE B'[Qty] ) )
)

Does a measure like this give you the result you expect?

 

Regards,

Owen


Owen Auger
Did I answer your question? Mark my post as a solution!
Blog
LinkedIn

Owen, the result is exactly what i expected.  Smiley Very Happy

Great, and thankyou so mutch! 

Hope I'll become more skilled in this sense Smiley Wink

Thank you again!

 

Alessandro M.

 

 

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