Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Join the Fabric FabCon Global Hackathon—running virtually through Nov 3. Open to all skill levels. $10,000 in prizes! Register now.

Reply
manuelfigueirat
Frequent Visitor

Multiple aggregation Distinct Count (3 Filters)

Hello Everyone,

 

I´m trying to get to count (distinct) how many times a Pallet Code was used multiple times for different deliveries within the same shipment Number --> A shipment can contain multiple Deliveries and the deliveries can have the same pallet code

 

Shipment NumberDelivery NumberPallet CodeDISTINCTCOUNT Expected Output
23485553
23465553
23455553

 


The example above contains one Shipment Number (555) with multiple deverlies where they all used the same Pallet Code, menaing the pallet code has been used 3 times within the same Shipment and multiple deliveries

 

I used this, but seems not working well:

 

 

 

 

Countv1 = COUNTROWS(FILTER(SSCC, SSCC[Shipment Number] = EARLIER(SSCC[Shipment Number]) && SSCC[Pallet Code] = EARLIER(SSCC[Pallet Code])))

 

 

 

 

Many thanks!

1 ACCEPTED SOLUTION
amitchandak
Super User
Super User

@manuelfigueirat , if this is a column, this seems fine

 

countx(filter( SSCC, SSCC[Shipment Number] = EARLIER(SSCC[Shipment Number]) && SSCC[Pallet Code] = EARLIER(SSCC[Pallet Code])),[Shipment Number])

 

for measure

 

countx(filter(allselected( SSCC), SSCC[Shipment Number] = MAX(SSCC[Shipment Number]) && SSCC[Pallet Code] = MAX(SSCC[Pallet Code])),[Shipment Number])

Share with Power BI Enthusiasts: Full Power BI Video (20 Hours) YouTube
Microsoft Fabric Series 60+ Videos YouTube
Microsoft Fabric Hindi End to End YouTube

View solution in original post

1 REPLY 1
amitchandak
Super User
Super User

@manuelfigueirat , if this is a column, this seems fine

 

countx(filter( SSCC, SSCC[Shipment Number] = EARLIER(SSCC[Shipment Number]) && SSCC[Pallet Code] = EARLIER(SSCC[Pallet Code])),[Shipment Number])

 

for measure

 

countx(filter(allselected( SSCC), SSCC[Shipment Number] = MAX(SSCC[Shipment Number]) && SSCC[Pallet Code] = MAX(SSCC[Pallet Code])),[Shipment Number])

Share with Power BI Enthusiasts: Full Power BI Video (20 Hours) YouTube
Microsoft Fabric Series 60+ Videos YouTube
Microsoft Fabric Hindi End to End YouTube

Helpful resources

Announcements
September Power BI Update Carousel

Power BI Monthly Update - September 2025

Check out the September 2025 Power BI update to learn about new features.

FabCon Atlanta 2026 carousel

FabCon Atlanta 2026

Join us at FabCon Atlanta, March 16-20, for the ultimate Fabric, Power BI, AI and SQL community-led event. Save $200 with code FABCOMM.

Top Solution Authors
Top Kudoed Authors