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MadisMerk
Helper I
Helper I

Measure question

Can you help me with a measure? Let us imagine I have this table as a starting point

Vehicle number

Customer name

Vehicle type

Amount

550 RLA

Toomas

New

1

885 ASS

Toomas

Used

1

854 PPT

Toomas

New

1

754 TYU

Anne

Used

1

125 ASK

Anne

Used

1

855 ANN

Juss

New

1

999 SVE

Juss

Used

1

 

I would like to now only show the customers and the amounts for customers that have only used vehicles and no new ones. So the end result would look like this:

 

Customer name

Amount

Anne

2

1 ACCEPTED SOLUTION
Zubair_Muhammad
Community Champion
Community Champion

@MadisMerk 

 

Try this MEASURE

 

Measure =
IF (
    COUNTROWS ( VALUES ( TableName[Vehicle type] ) ) = 1
        && CALCULATE (
            DISTINCTCOUNT ( TableName[Vehicle type] ),
            TableName[Vehicle type] = "Used"
        ) = 1,
    COUNT ( TableName[Vehicle type] )
)

View solution in original post

2 REPLIES 2
Zubair_Muhammad
Community Champion
Community Champion

@MadisMerk 

 

Try this MEASURE

 

Measure =
IF (
    COUNTROWS ( VALUES ( TableName[Vehicle type] ) ) = 1
        && CALCULATE (
            DISTINCTCOUNT ( TableName[Vehicle type] ),
            TableName[Vehicle type] = "Used"
        ) = 1,
    COUNT ( TableName[Vehicle type] )
)
MattAllington
Community Champion
Community Champion

It is not easy to do this with 1 table. You should load a customer dimension table too, containing all unique customers. Join this to your data table with a 1 to many relationship. Then put the customer from the customer table into the rows of a matrix. The measures would be

Total new = calculate(sum(datatable[amount]),datatable[vehicle type]=“new”)

Total but only customers with no new vehicles =calculate(sum(datatable[amount]),filter(customertable,[total new]=0))

 

i haven’t tested this, but it think it is correct. 



* Matt is an 8 times Microsoft MVP (Power BI) and author of the Power BI Book Supercharge Power BI.
I will not give you bad advice, even if you unknowingly ask for it.

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