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rakesh-k01
Frequent Visitor

Matrix on the same column

Hi,

 

I have 2 tables having 1 to many relationship with the ref2per table. Capture.PNG

 

I' am trying to get a matrix something like below:

 

nameSAPPCSEventBrite
SAP  1
PCS 1 
EventBrite1 1

SAP and EventBrite has count 1 since person id 1 is shared between them. Same applies on the other way round.  Since person id 2 has only one reference, the value is 1 for matrix EventBrite to EventBrite. 

 

Just using the UI I'am getting the below result.

Capture3.PNG

 

 

 

 

 

 

 

 

 

 I'am still a rookie with the DAX commands, so any thoughts on how the required result can be achieved. 

 

Thanks

Rakesh

 

1 ACCEPTED SOLUTION
v-qiuyu-msft
Community Support
Community Support

Hi @rakesh-k01,

 

You can create calculated columns in ref2per table like below:

 

Name = RELATED('ref_table'[name])

 

Name(update) = var t=CALCULATE(MAX('ref2per'[ref_source_system_id]),ALLEXCEPT(ref2per,'ref2per'[personal_id]))
return
IF('ref2per'[ref_source_system_id]<> t,CALCULATE(MIN('ref2per'[Name]),ALLEXCEPT(ref2per,'ref2per'[personal_id])),
 CALCULATE(MAX('ref2per'[Name]),ALLEXCEPT(ref2per,'ref2per'[personal_id])))

 

q4.PNG

 

Best Regards,
Qiuyun Yu

Community Support Team _ Qiuyun Yu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-qiuyu-msft
Community Support
Community Support

Hi @rakesh-k01,

 

You can create calculated columns in ref2per table like below:

 

Name = RELATED('ref_table'[name])

 

Name(update) = var t=CALCULATE(MAX('ref2per'[ref_source_system_id]),ALLEXCEPT(ref2per,'ref2per'[personal_id]))
return
IF('ref2per'[ref_source_system_id]<> t,CALCULATE(MIN('ref2per'[Name]),ALLEXCEPT(ref2per,'ref2per'[personal_id])),
 CALCULATE(MAX('ref2per'[Name]),ALLEXCEPT(ref2per,'ref2per'[personal_id])))

 

q4.PNG

 

Best Regards,
Qiuyun Yu

Community Support Team _ Qiuyun Yu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Hi @v-qiuyu-msft

 

Awesome! That worked. Thanks a ton.

 

Thanks & Regards,

Rakesh

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