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mshaikh
Regular Visitor

MS - Measure Conditional formula

Hi,

 

I am looking for Conditional measure formula using 2 tables. Following sample file is attached for reference.

 

Can someone please provide suitable measure formula in order to calculate expected result.

 

Thanks in advance.

 

SMSample.png

 

1 ACCEPTED SOLUTION
v-piga-msft
Resident Rockstar
Resident Rockstar

Hi @mshaikh,

 

Firstly, you could create the relatioship with the table A and B with Key column.

 

Then you could create the calculated column for Table-B with the formula below.

 

Column =
IF (
    CALCULATE ( MAX ( 'Table-A'[A01-KEY] ) )
        = CALCULATE ( MAX ( 'Table-B'[B01-KEY] ) )
        && CALCULATE ( MAX ( 'Table-B'[B01-Type] ) ) = 99,
    CALCULATE (
        SUM ( 'Table-A'[A01-Amount] ),
        FILTER ( 'Table-B', 'Table-B'[B01-KEY] = EARLIER ( 'Table-B'[B01-KEY] ) )
    ),
    0
)

Then you will get the output you like.

 

 ouput.PNG

 

If you still need help, please share your desired output so that we could help further on it.

 

Best  Regards,

Cherry

Community Support Team _ Cherry Gao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

1 REPLY 1
v-piga-msft
Resident Rockstar
Resident Rockstar

Hi @mshaikh,

 

Firstly, you could create the relatioship with the table A and B with Key column.

 

Then you could create the calculated column for Table-B with the formula below.

 

Column =
IF (
    CALCULATE ( MAX ( 'Table-A'[A01-KEY] ) )
        = CALCULATE ( MAX ( 'Table-B'[B01-KEY] ) )
        && CALCULATE ( MAX ( 'Table-B'[B01-Type] ) ) = 99,
    CALCULATE (
        SUM ( 'Table-A'[A01-Amount] ),
        FILTER ( 'Table-B', 'Table-B'[B01-KEY] = EARLIER ( 'Table-B'[B01-KEY] ) )
    ),
    0
)

Then you will get the output you like.

 

 ouput.PNG

 

If you still need help, please share your desired output so that we could help further on it.

 

Best  Regards,

Cherry

Community Support Team _ Cherry Gao
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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