Forum Discussion
Anonymous
9 years agoNot applicable
Infinity value, inserting if isblank problem
approved of approvable = CALCULATE(COUNTROWS(LNApps_Facts),'LNApps_Facts'[FICO_SCORE]>600)/ CALCULATE(count(LNApps_Facts[FICO_SCORE]), LNApps_ApplicationDim[Status] ="Approved",LNApps_ApplicationDim[...
- 9 years ago
EDITED:
Anonymous
Change the commas to the OR operator like this...
approved of approvable = DIVIDE ( CALCULATE ( COUNTROWS ( LNApps_Facts ), 'LNApps_Facts'[FICO_SCORE] > 600 ), CALCULATE ( COUNT ( LNApps_Facts[FICO_SCORE] ), LNApps_ApplicationDim[Status] = "Approved" || LNApps_ApplicationDim[Status] = "Funds_Released" || LNApps_ApplicationDim[Status] = "Booked" ), 0 )It should work now :smileyhappy:
- 9 years ago
Anonymous
Well this time you have to use the AND operator
approved of approvable = DIVIDE ( CALCULATE ( COUNTROWS ( LNApps_Facts ), 'LNApps_Facts'[FICO_SCORE] >= 600 && 'LNApps_Facts'[FICO_SCORE] <= 850 ), CALCULATE ( COUNT ( LNApps_Facts[FICO_SCORE] ), LNApps_ApplicationDim[Status] = "Approved" || LNApps_ApplicationDim[Status] = "Funds_Released" || LNApps_ApplicationDim[Status] = "Booked" ), 0 )Good Luck! :smileyhappy:
Anonymous
9 years agoNot applicable
Quick question, what's the easiest way to add to that same formula to have scores >=600 but <=850?
Sean
9 years agoCommunity Champion
Anonymous
Well this time you have to use the AND operator
approved of approvable =
DIVIDE (
CALCULATE (
COUNTROWS ( LNApps_Facts ),
'LNApps_Facts'[FICO_SCORE] >= 600
&& 'LNApps_Facts'[FICO_SCORE] <= 850
),
CALCULATE (
COUNT ( LNApps_Facts[FICO_SCORE] ),
LNApps_ApplicationDim[Status] = "Approved"
|| LNApps_ApplicationDim[Status] = "Funds_Released"
|| LNApps_ApplicationDim[Status] = "Booked"
),
0
)Good Luck! :smileyhappy: