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parisaranda
New Member

How to measure the sum of X table (of this semester) / the sum of X table (of the last semester)

Hello and happy thanksgiving for you all,

 

I am having this issue with this tables and the formula should be:

 

sum(Matriculados) / sum(Matriculados (semester -1))
 
But I was not able to had a proper calculation, since I am here: 
 
 Now, I have the semester as the column name "Año" where it shows as an integer the year and "Semester" that shows 1 and 2. Also, the "Matriculados" column is an integer.
 
I would be glad to know that there is a way to calculate the required formula.
 
Thank you for your time. 
1 ACCEPTED SOLUTION
v-rzhou-msft
Community Support
Community Support

Hi @parisaranda ,

I build a sample to have a test. Firstly add a calculated column : Rank by Year and Semester.

Rank by Year and Semester = RANKX('Table','Table'[Año]*10+'Table'[Semester],,ASC,Dense)

1.png

Measure:

Sum of X table (of this semester) / Sum of X table (of the last semester) = 
VAR _THIS_Semester =
    CALCULATE ( SUM ( 'Table'[Matriculados] ) )
VAR _LAST_Semester =
    CALCULATE (
        SUM ( 'Table'[Matriculados] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Rank by Year and Semester]
                = MAX ( 'Table'[Rank by Year and Semester] ) - 1
        )
    )
RETURN
    DIVIDE ( _THIS_Semester, _LAST_Semester )

Result is as below.

1.png

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

2 REPLIES 2
v-rzhou-msft
Community Support
Community Support

Hi @parisaranda ,

I build a sample to have a test. Firstly add a calculated column : Rank by Year and Semester.

Rank by Year and Semester = RANKX('Table','Table'[Año]*10+'Table'[Semester],,ASC,Dense)

1.png

Measure:

Sum of X table (of this semester) / Sum of X table (of the last semester) = 
VAR _THIS_Semester =
    CALCULATE ( SUM ( 'Table'[Matriculados] ) )
VAR _LAST_Semester =
    CALCULATE (
        SUM ( 'Table'[Matriculados] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Rank by Year and Semester]
                = MAX ( 'Table'[Rank by Year and Semester] ) - 1
        )
    )
RETURN
    DIVIDE ( _THIS_Semester, _LAST_Semester )

Result is as below.

1.png

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

ryan_mayu
Super User
Super User

@parisaranda 

could you pls provide the sample data and expected output?





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