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saivina2920's avatar
saivina2920
Post Prodigy
4 years ago
Solved

How to get weekwise count

I have the below data. i want to get count of empno in y axis and get count weekwise of using EmpRelieve Date in x axis. The below example shows E101A contains 3 records. we just want to eliminate l...
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  • Anonymous's avatar
    Anonymous
    4 years ago

    Hi saivina2920 , 

     

    Here's my solution.

    1.Create a calculated column to remove "_MN" and "_DN". 

    EmpNo without MN/DN =
    IF (
    CONTAINSSTRING ( [EmpNo], "_MN" ) = TRUE ()
    || CONTAINSSTRING ( [EmpNo], "_DN" ) = TRUE (),
    LEFT ( [EmpNo], LEN ( [EmpNo] ) - 3 ),
    [EmpNo]
    )

     

     

    2.Create a calendar table. And sort the Year-Weeknum column by the sort column.

    Calendar =
    ADDCOLUMNS (
    CALENDAR ( MIN ( 'Table'[EmpRelieve Date] ), MAX ( 'Table'[EmpRelieve Date] ) ),
    "Year-WeekNum",
    YEAR ( [Date] ) & "-"
    & WEEKNUM ( [Date], 2 ),
    "sort",
    YEAR ( [Date] ) * 100
    + WEEKNUM ( [Date], 2 )
    )

    3.Create the following visual. Select "Count(Distinct)".

    You can check more details from my attachment.

     

     

     

    Best Regards,

    Stephen Tao

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

Anonymous's avatar
Anonymous
Not applicable
4 years ago

Hi saivina2920 , 

 

Here's my solution.

1.Create a calculated column to remove "_MN" and "_DN". 

EmpNo without MN/DN =
IF (
CONTAINSSTRING ( [EmpNo], "_MN" ) = TRUE ()
|| CONTAINSSTRING ( [EmpNo], "_DN" ) = TRUE (),
LEFT ( [EmpNo], LEN ( [EmpNo] ) - 3 ),
[EmpNo]
)

 

 

2.Create a calendar table. And sort the Year-Weeknum column by the sort column.

Calendar =
ADDCOLUMNS (
CALENDAR ( MIN ( 'Table'[EmpRelieve Date] ), MAX ( 'Table'[EmpRelieve Date] ) ),
"Year-WeekNum",
YEAR ( [Date] ) & "-"
& WEEKNUM ( [Date], 2 ),
"sort",
YEAR ( [Date] ) * 100
+ WEEKNUM ( [Date], 2 )
)

3.Create the following visual. Select "Count(Distinct)".

You can check more details from my attachment.

 

 

 

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

  • saivina2920's avatar
    saivina2920
    Post Prodigy
    4 years ago

    It's Perfect...