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robertosangi
Helper I
Helper I

Highest value per cluster

Hi, 

 

In my case I want to obtain the highest value (top 1) of a column divided per cluster. Here the example:

robertosangi_0-1646208711449.png


Actually I filtered my column as per picture because is not possible to filter per TOP N:

robertosangi_1-1646208754087.png

 

As you can se from the image "Palermo Ovest" in this case has only one row and it is ok but "Partinico" has different values because of many cases greater than 10. 

How can I show only the highest per each cluster in bold.

Thanks 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @robertosangi ,

 

According to your screenshot, I think your table should look like as below.

1.png

I think you want to show values in red box.

1.png

I suggest you to create a rank measure and use it as a filter in visual level filter.

RANK =
VAR _RANK =
    RANKX (
        ALLEXCEPT ( 'Table', 'Table'[Unite], 'Table'[Blue Team] ),
        CALCULATE ( SUM ( 'Table'[IGB_NoLoc] ) ),
        ,
        DESC,
        DENSE
    )
RETURN
    _RANK

Result is as below.

1.png

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

7 REPLIES 7
amitchandak
Super User
Super User

@robertosangi , Create a rank on the innermost column and filter on 10

 

rankx(allselected(Table[cluster]), [IGB],,desc,dense)

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Hi @amitchandak , i don't want to filter on 10 but on the maximum value. It is possible?

Anonymous
Not applicable

Hi @robertosangi ,

 

Do you want to filter your matrix visual by two filters, 1. values in IGB_Noloc are greater than 10, 2. maxest value in  IGB_Noloc in per cluster ?

Here I suggest you to create a measure to filter your visual.

My sample:

1.png

Measure:

IGB_NoLoc Greater than 10 and Top 1 =
VAR _IGB_NoLoc =
    CALCULATE (
        SUM ( 'Table'[Value] ),
        FILTER ( 'Table', 'Table'[Type] = "IGB_NoLoc" )
    )
VAR _MAX_IGB_NoLoc =
    CALCULATE (
        MAX ( 'Table'[Value] ),
        FILTER (
            ALL ( 'Table' ),
            'Table'[Unite] = MAX ( 'Table'[Unite] )
                && 'Table'[Level2] = MAX ( 'Table'[Level2] )
                && 'Table'[Type] = "IGB_NoLoc"
                && 'Table'[Value] > 10
        )
    )
RETURN
    IF ( _IGB_NoLoc = _MAX_IGB_NoLoc, 1, 0 )

Add this measure into visual level filter of matrix and set it show items when value =1.

Result is as below.

2.png

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Hi @Anonymous thanks for your reply. I want to filter only per the highest value if possibile. Not filtering per 10 value

Anonymous
Not applicable

Hi @robertosangi ,

 

I think my measure will show you the highest value in IGB_Noloc. If this still couldn't help you solve your problem, please show me a screenshot with the result you want, this will make me easier to find the solution.

 

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Hi @Anonymous,

Sure, I'll try to explain better

robertosangi_0-1646644355587.png


As you can see this is the AS IS situation. I want, per each red category, the highest IGB_NoLoc value. So, in this case for PALERMO EST only the first and the third value. In PALERMO OVEST only the first.

It is clear? I'll try to explain better if not.

 

Thanks

Anonymous
Not applicable

Hi @robertosangi ,

 

According to your screenshot, I think your table should look like as below.

1.png

I think you want to show values in red box.

1.png

I suggest you to create a rank measure and use it as a filter in visual level filter.

RANK =
VAR _RANK =
    RANKX (
        ALLEXCEPT ( 'Table', 'Table'[Unite], 'Table'[Blue Team] ),
        CALCULATE ( SUM ( 'Table'[IGB_NoLoc] ) ),
        ,
        DESC,
        DENSE
    )
RETURN
    _RANK

Result is as below.

1.png

Best Regards,
Rico Zhou

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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