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MikePowerBI
Helper II
Helper II

Have Week Start on Saturday in Date Column

Hi there,

 

I am looking to create weekly buckets to sort data within a date column, so that the week starts on a Saturday and ends on a Friday. For example: Saturday, October 1, 2022 through Friday, October 7, 2022 should display October 1, 2022. And Saturday, October 8, 2022 through Friday, October 14, 2022 should display October 8, 2022.

 

I used the following formula: 'Date'[Date] - WEEKDAY('Date'[Date], 2) - 1, but this did not have the desired outcome because the column is still using Monday as the start day for each week. Additionally, I tried changing the arguements to the WEEDAY function, but it appears I am only allowed to enter in 1 through 3. 

 

Any help with with this would be greatly appreciated. 

 

MikePowerBI_0-1666210155736.png

 

1 ACCEPTED SOLUTION

Thanks for the clarification @Greg_Deckler ! I was able to get the same results using "+1" at the end of formula instead of "-1"

 

MikePowerBI_0-1666212296981.png

 

View solution in original post

4 REPLIES 4
Greg_Deckler
Super User
Super User

@MikePowerBI 

'Date'[Date] - WEEKDAY('Date'[Date], 16) - 1


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DAX is easy, CALCULATE makes DAX hard...

Hi @Greg_Deckler ,

 

Thank you for the prompt reply! Unfortunately, the formula provided did not have the desired outcome. I was able to brute force the desired outcome using a long "if" statement. 

 

Thanks again!

 

MikePowerBI_0-1666211013689.png

 

 Using 16 as the second parameter of weekday returns Saturday = 1 and Friday = 7.WEEKDAY('Date'[Date], 16)

 

@MikePowerBI



Follow on LinkedIn
@ me in replies or I'll lose your thread!!!
Instead of a Kudo, please vote for this idea
Become an expert!: Enterprise DNA
External Tools: MSHGQM
YouTube Channel!: Microsoft Hates Greg
Latest book!:
Power BI Cookbook Third Edition (Color)

DAX is easy, CALCULATE makes DAX hard...

Thanks for the clarification @Greg_Deckler ! I was able to get the same results using "+1" at the end of formula instead of "-1"

 

MikePowerBI_0-1666212296981.png

 

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