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I have a Table of three Columns
| Date | Season | Bottles |
| 14/12/2020 | 19 | 16 |
| 12/08/2020 | 19 | 21.4 |
| 11/06/2021 | 20 | 64 |
| 11/08/2021 | 21 | 51 |
| 5/11/2021 | 21 | 14 |
| 10/10/2022 | 22 | 15.3 |
1) Sum the Bottle quantity by Season number then
2) I need to Find the Difference From
---Calculate(SUM[Bottles] WHERE season = MAX[season] - SUM[Bottles ] WHERE season = SECONDMAX [season])
My question is
If i want Selelct Maximum Value - Max[season],
How can i select second MAX value
Hi,
Please show the expected result clearly.
Hi @heygowtam
Use this DAX expression to find the Second Max date:
Second Max =
Var _Max = MAX( 'Table'[Date] )
return
CALCULATE(MAX( 'Table'[Date] ),REMOVEFILTERS('Table'),'Table'[Date]<_Max)
If this post helps, please consider accepting it as the solution to help the other members find it more quickly.
Appreciate your Kudos!!
@VahidDM
Thanks for your Reply,
I need to pick second highest Season value,
then subtract from first maximum [Season ] Value,
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