Get certified for free when you join Fabric Data Days 2026 and dive into Fabric, Power BI, SQL, AI, and other essential data skills.
Join nowJuly 7 - July 17 | Round 2 of the Power BI Dataviz World Championships. Don't miss your chance! Learn more
First up, sorry if this was already asked and solved, i didn't manage to find anything on similar to what i want.
I have a table with a ID, a group and a Class, and i want a function that returns the id of the [only] other Class equal on the group
As the example, there are 10 itens per group, and 5 classes (that are always numbers from 1-5). I'm trying to manipulate the tables but i ultimatelly failed.
ID Group Class ---What i Want---
1 1 1 9
2 1 3 7
3 1 5 6
4 1 2 10
5 1 4 8
6 1 5 3
7 1 3 2
8 1 4 5
9 1 1 1
10 1 2 4
Any help?
Solved! Go to Solution.
Hi @ebuttazzi,
We can create a calculated column based on your data.
Column = CALCULATE(SUM(Table1[ID]),FILTER(ALL(Table1),Table1[Class]=EARLIER(Table1[Class])))-Table1[ID]
Then we can get the result as you need.
For more details, please check the pbix as attached.
Regards,Frank
Hi @ebuttazzi,
We can create a calculated column based on your data.
Column = CALCULATE(SUM(Table1[ID]),FILTER(ALL(Table1),Table1[Class]=EARLIER(Table1[Class])))-Table1[ID]
Then we can get the result as you need.
For more details, please check the pbix as attached.
Regards,Frank
Hey Frank, First, i would like to thank you for the solution, i was not aware of the existence of the EARLIER func.
Your solution would work great if not the fact that ALL(table) messes values up when there are more than one group. I manage to work aroud it using:
ID counterpart = CALCULATE(SUM(table[id]);FILTER(FILTER(table[group] = EARLIER(table[group]));table[class]=EARLIER(table[class]))) - table[id]
I just wondered if my solution for the group filtering (that works) is the most efficient.
Again, Thank you a lot for helping me out with this issue, i wish you the best.
Enzo
Join us in Barcelona for FabCon and SQLCon, the Fabric, Power BI, SQL, and AI community event. Save €200 with code FABCMTY200.
Join Fabric Data Days 2026: 60 days of free live/on-demand sessions, challenges, study groups, and certification opportunities.
| User | Count |
|---|---|
| 22 | |
| 22 | |
| 18 | |
| 17 | |
| 13 |
| User | Count |
|---|---|
| 61 | |
| 52 | |
| 47 | |
| 41 | |
| 38 |