Get Minimum of Group within Column but handle duplicate values

[Anonymous]

So I have a price column by day. This column can contain duplicates. I'm trying to create a column that returns "Y" when the value in the Price column is the Minimum amount. However, I only want to return one "Y" even though there can be two or more minimum prices. Is there a way to handle this? This is what I have:

Min Indicator =
IF (
    CALCULATE (
        MIN ( 'Historical'[Price] ),
        FILTER (
            'Historical',
            'Historical'[Rank Key] = EARLIER ( 'Historical'[Rank Key] )
        )
    ) = [Price],
    "Y",
    "N"
)

But if the minimum price shows up twice, it returns two "Y" values which I don't want.

[v-eqin-msft · Accepted solution]

Hi @Anonymous ,

Please try the following formula to create a column after adding a Index column:

Min Indicator =
VAR _min =
    CALCULATE (
        MIN ( 'Historical'[Price] ),
        ALLEXCEPT ( Historical, Historical[Rank Key] )
    )
VAR _first =
    MINX (
        FILTER (
            'Historical',
            'Historical'[Rank Key] = EARLIER ( 'Historical'[Rank Key] )
                && 'Historical'[Price] = _min
        ),
        [Index]
    ) 
//Or use FIRSTNONBLANK()
// var _f =
// CALCULATE (
//     FIRSTNONBLANK ( 'Historical'[Index], TRUE () ),
//     FILTER (
//         'Historical',
//         'Historical'[Rank Key] = EARLIER ( Historical[Rank Key] )
//             && 'Historical'[Price] = _min
//     )
// )

RETURN
    IF ( _first = [Index], "Y", "N" )

The final output is shown below:

Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[sayaliredij]

You can try using RANKX instead of finding out the Minimum and assign Y when the rank is 1 

This way you can probably solve the issue.