Forum Discussion
Get Date difference with minutes if possible between first occurrence and last occurrence.
In the screenshot attached A has occurred four times and first occurrence is on 01/01/2020 11:20 and last occurrence is 03/01/2020 11:29. So the date difference between these two is 2 days 9 minutes. (1449 min). Calculation difference in hours or in muntes or in seconds will also work.
I need result table in Power like
A 1449
B X
C X..
- Anonymous6 years ago
Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)
4 Replies
- amitchandak
Super User
You have view data based on column 1
and create a measure to take diff
measure = datediff(Min(Table[Date]),Max(Table[Date]),Minute)
- Greg_Deckler
Community Champion
DATEDIFF([Date1],[Date2],MINUTE)
- v-lionel-msft
Community Support
Hi Anonymous ,
Try this measure:
Measure = VAR Min_ = CALCULATE( MIN(Sheet4[Date/time]), ALLEXCEPT( sheet4, Sheet4[Item] ) ) VAR Max_ = CALCULATE( MAX(Sheet4[Date/time]), ALLEXCEPT( Sheet4, Sheet4[Item] ) ) RETURN Measure 2 = DATEDIFF( [Min_], [Max_], MINUTE )2 days 9 mins = 24*60*2 + 9 = 2889
Best regards,
Lionel ChenIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- AnonymousNot applicable
Came to know later that simple below measure will also work
DateDiff in Hours = DATEDIFF(MIN(B),MAX(B),HOUR)