Forum Discussion
Asina
3 years agoHelper III
Finding paths connected through a node. Data filtering
I have a table which resembles the below. The columns explained: Main contains the name and the pathway number. The Main can therefore contain nodes called Str1 or Str2, which indicates where it...
- 3 years ago
Try
Connected Mains = VAR InitialNodes = UNION( VALUES( 'Table'[Str1] ), VALUES( 'Table'[Str2] ) ) VAR ConnectedMains = CALCULATETABLE( VALUES( 'Table'[Main] ), 'Table'[Str1] IN InitialNodes || 'Table'[Str2] IN InitialNodes, REMOVEFILTERS( 'Table' ) ) VAR ConnectedMainsExlcudingCurrent = EXCEPT( ConnectedMains, { SELECTEDVALUE( 'Table'[Main] ) } ) VAR Result = CONCATENATEX( ConnectedMainsExlcudingCurrent, 'Table'[Main], ", " ) RETURN Result - 3 years ago
If I understand correctly you want a list of mains and all the nodes they are connected to. You could do another table like
Main All Connected = GENERATE ( ALLNOBLANKROW ( 'Main Neighbours'[Radialnr-rettet] ), DISTINCT ( UNION ( CALCULATETABLE ( VALUES ( 'Main Neighbours'[Connected To] ) ), CALCULATETABLE ( VALUES ( 'Main Neighbours'[Neighbours Neighbour] ) ) ) ) )
Asina
3 years agoHelper III
Thank you, it does work for the Neighbors Neighbor column 👍.
What I meant with a second column, was that a column that sums the total of filtered.
In this: Main + Neighbor of Main + Neighbors Neighbor. This makes the table large. But, I can use this new column to connect to the picture table and then have the problem solved. is it possible ?
johnt75
3 years agoSuper User
If I understand correctly you want a list of mains and all the nodes they are connected to. You could do another table like
Main All Connected =
GENERATE (
ALLNOBLANKROW ( 'Main Neighbours'[Radialnr-rettet] ),
DISTINCT (
UNION (
CALCULATETABLE ( VALUES ( 'Main Neighbours'[Connected To] ) ),
CALCULATETABLE ( VALUES ( 'Main Neighbours'[Neighbours Neighbour] ) )
)
)
)